Try B. The handle on the faucet. It stops the energy and lets it flow like how the switch lets the energy flow but then stops it also
Operating capital - Operating capital refers to that amount of cash required to run day to day working or operation of business .
Total Operating Capital = Total assets (short term + long term) - current liabilities
total assets include inventories, accounts receivable , fixed assets etc.
current liabilities include account payables, accrued expenses, income tax accrued interest etc.
NOWC means net operating working capital it is difference between current assets and non interest bearing current liabilities
Current assets include cash accounts receivable and inventories and exclude marketable securities
Non interest bearing current liabilities means amount of money company must pay within a year without own interest.
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Answer:
T= 224.01 N
Explanation:
in imminent motion we have to :
- The frictional force reaches its maximum value
- The system is in balance of forces
Data
W= 500 N : weight of the log
μs = 0.5
μk = 0.35
α = 30°above the ground : angle of the cable attached to the log
Newton's first law to the log:
∑F =0 Formula (1)
∑F : algebraic sum of the forces in Newton (N)
Forces acting on the log
T: cable tension for impending movement
N: normal force
W : weight
f: frictional force , f= μsN
We apply the formula (1)
∑Fx=0
Tx-f = 0
Tcosα-μsN=0
Tcos30°-0.5N=0 Equation (1)
∑Fy=0
N+Ty-W=0
N+Tsin30°-500=0
N= 500-Tsin30° Equation (2)
We replace the value of N of the Equation (2) in the equation (1)
Tcos30°-0.5(500-Tsin30°) = 0
Tcos30°+0.5Tsin30° = 0.5*500
T( cos30°+0.5*sin30°) = 250
(1.116) T = 250
T= 250/1.116
T= 224.01 N
Answer:
A=0.199
Explanation:
We are given that
Mass of spring=m=450 g=
Where 1 kg=1000 g
Frequency of oscillation=
Total energy of the oscillation=0.51 J
We have to find the amplitude of oscillations.
Energy of oscillator=
Where =Angular frequency
A=Amplitude
Using the formula
Hence, the amplitude of oscillation=A=0.199
We will use formula for the orbital velocity of Venus, which is v = 35.02 km/s.
An average distance to the Sun ( In kilometers ) is:
R = 0.723 * 149,579,871 km= 108,150,260 km.
Than we will calculate the orbital period ( T ).
v = 2 π R / T
T = 2 π R / v
T = 2 * 3.14 * 108,150,260 km / 126,072 km/s
T = 5389.75 s ≈ 224.5 days
The orbital period of Venus is approximately 224.5 days.