Define average speed velocity

The velocity of a particle is given by v=20t² - 100t + 50, where v is in meters per second and t is in seconds. Evaluate the vel

allochka39001 [22]

Explanation:

It is given that,

The velocity of a particle is given by :

$v=20t^2-100t+50$

Where

v is in m/s and t is in seconds

Let a is the acceleration of the object at time t. So,

$a=\dfrac{dv}{dt}$

$a=\dfrac{d(20t^2-100t+50)}{dt}$

$a=40t-100$

When a = 0

$40t-100=0$

t = 2.5 s

a is zero at t = 2.5 s. Velocity, $v=20(2.5)^2-100(2.5)+50$

v = -75 m/s

Since, $v=\dfrac{ds}{dt}$ , s is the distance travelled

$s=\int\limits{vdt}$

$s=\int\limits{(20t^2-100t+50)dt}$

$s=\dfrac{20t^3}{3}-50t^2+50t$

At t = 2.5 s, $s=\dfrac{20(2.5)^3}{3}-50(2.5)^2+50(2.5)$

s = −83.34 m

Hence, this is the required solution.

5 0

3 years ago

Read 2 more answers

From the window of a building, a ball is tossed from a height y0 above the ground with an initial velocity of 8.10 m/s and angle

GarryVolchara [31]

Answer:

Part a)

$y = 88.5 m$

Part b)

$v_x = 7.7 m/s$

$v_y = 2.5 m/s$

Part c)

equation of position in x direction is given as

$x = v_x t$

equation of position in y direction is given as

$y = v_y t + \frac{1}{2}gt^2$

Part d)

$x = 30.8 m$

Part e)

H = 88.5 m

Part f)

t = 1.2 s

Explanation:

As we know that ball is projected with speed

v = 8.10 m/s at an angle 18 degree below the horizontal

so we will have

$v_x = 8.10 cos18$

$v_x = 7.7 m/s$

$v_y = 8.10 sin18$

$v_y = 2.5 m/s$

Part a)

Since it took t =4 s to reach the ground

so its initial y coordinate is given as

$y = v_y t + \frac{1}{2}a_y t^2$

$y = 2.5(4) + \frac{1}{2}(9.81)(4^2)$

$y = 88.5 m$

Part b)

components of the velocity is given as

$v_x = 8.10 cos18$

$v_x = 7.7 m/s$

$v_y = 8.10 sin18$

$v_y = 2.5 m/s$

Part c)

equation of position in x direction is given as

$x = v_x t$

equation of position in y direction is given as

$y = v_y t + \frac{1}{2}gt^2$

Part d)

distance where it will strike the floor is given as

$x = v_x t$

$x = 7.7 \times 4$

$x = 30.8 m$

Part e)

Height from which it is thrown is same as initial y coordinate of the ball

so it is given as

H = 88.5 m

Part f)

time taken by ball to reach 10 m below is given as

$y = v_y t + \frac{1}{2}gt^2$

$10 = 2.5t + \frac{1}{2}(9.81) t^2$

t = 1.2 s

7 0

3 years ago

Which of the following is an instantaneous speed?

Brilliant_brown [7]

Answer:

A: All of the above

Explanation:

The instantaneous speed of an object is simply the current seed of the object at any given time. The SI unit is m/S and it is a vector quantity.

Therefore, according to the given options, they all have SI units that are consistent with distance and time which makes them all an example of instantaneous speed.

5 0

3 years ago

A boy pushes on a wagon so that it accelerates at a rate of 0.50 m/s2. The wagon has a mass of 24 kg. What is the magnitude of t

IRISSAK [1]

Answer:

12N

Explanation:

Force acting on any body is equal to mass of body multiplied by acceleration produced in the body.

Its formula is

F = M*a

where F is the force acting on body

M is the mass of the body

a is the acceleration produced in the body

Unit of force is Newton represented by N

1 N is force acting on body of mass 1 kg which produces acceleration of 1m/s^2.

_____________________________________

Given

a = 0.50 m/s^2

M = 24 kg

therefore

F = 24*0.5 = 12 N

Thus, magnitude of the boy's pushing force is 12 N.

4 0

4 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Vanyuwa [196]

A build up of charges on a sock from a dryer

5 0

3 years ago

Define average speed velocity​

Define average speed velocity