Answer:
Let l be the length and w the width of the rectangle.
P as the perimeter and A as the area.
length of a rectangle is four times the width:
w = w
l = 4w
System of equation : 2l + 2w = P
Substitute:
2(4w) + 2w = 45
8w + 2w
10w = 45
w = 45 / 10
w = 4.5
Solve for l:
l = 4w
l = 4(4.5)
l = 18
Area:
A = lw
A = 18(4.5)
A = 81 in²
I am pretty confident its 1.0
The area of the room must equal the sum of the areas of the tiles...
20*30=n(2*3)
600=6n
n=100
So 100 tiles are needed.
Given:
Two planks are each 1.5 m long.
One plank is 2.5m long.
To find:
The total length of all the three planks.
Solution:
Two planks are each 1.5 m long. So,
First plank = 1.5 m
Second plank = 1.5 m
One plank is 2.5m long. So,
Third plank = 2.5 m
Now, the total length of all the three planks is



Therefore, the total length of all the three planks is 5.5 m.