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Genrish500 [490]
3 years ago
13

Joe’s cells can’t convert food energy effectively into energy they can use. As a result, he gets extremely tired, has weak legs,

and can’t breathe well. Joe swims every day to keep his body as strong as possible. Which organelle is affected by Joe's disease?
A. nucleus
B. mitochondrium
C. lysosome
D. chloroplast
Chemistry
2 answers:
aleksandr82 [10.1K]3 years ago
8 0
is the right answer
Bad White [126]3 years ago
5 0
The nucleus is effected

Explanation: The nucleus is the main part of it gets weak they all get weak
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An electrochemical cell is powered by the half reactions shown below.
andrezito [222]
Reduction reactions are those reactions that reduce the oxidation number of a substance. Hence, the product side of the reaction must contain excess electrons. The opposite is true for oxidation reactions. When you want to determine the potential difference expressed in volts between the cathode and anode, the equation would be: E,reduction - E,oxidation. 

To cancel out the electrons, the e- in the reactions must be in opposite sides. To do this, you reverse the equation with the negative E0, then replacing it with the opposite sign. 

Pb(s) --> Pb2+ +2e-      E0 = +0.13 V
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3 years ago
Calculate the volume of a 0.323-mol sample of a gas at 265 K and<br> 0.900 atm.
Katarina [22]

Answer:

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5 0
3 years ago
What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)
nikdorinn [45]

Answer : The volume of O_2 consumed are, 0.75\times 2\times 22.4 L.

Explanation :

The balanced chemical reaction will be:

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)

First we have to calculate the moles of Al.

\text{Moles of }Al=\frac{\text{Mass of }Al}{\text{Molar mass of }Al}

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\text{Moles of }Al=\frac{55g}{27g/mol}=2mole

Now we have to calculate the moles of O_2.

From the reaction we conclude that,

As, 4 mole of Al react with 3 moles of O_2

So, 2 mole of Al react with \frac{3}{4}\times 2=0.75\times 2 moles of O_2

Now we have to calculate the volume of O_2 consumed.

As we know that, 1 mole of substance occupies 22.4 liter volume of gas.

As, 1 mole of O_2 occupies 22.4 liter volume of O_2 gas

So, 0.75\times 2 mole of O_2 occupies 0.75\times 2\times 22.4 liter volume of O_2 gas

Therefore, the volume of O_2 consumed are, 0.75\times 2\times 22.4 L.

3 0
3 years ago
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The answer is; liquid phase

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3 0
3 years ago
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Metals are ductile,malleable,good conductors and shiny

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