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2 years ago

5

Which of the following tables represents a proportional relationship?

2 answers:

Nookie1986 [14]2 years ago

8 0

It's c. It's the one you have already answered

algol132 years ago

6 0

Answer:

You’re right!

Step-by-step explanation:

It IS 3, heres why:

it follows the same rule each time:

2X=Y

1 times 2 is 2

6 times 2 is 12

11 times 2 is 22

16 times 2 is 36

thats proportionate! :D

i hope this helps!

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Which table represents only values described by the relationship between a and b?

algol13

Answer:

a

Step-by-step explanation:

8 0

2 years ago

H(x)=(x^2)+1 and K(x)=-(x^2)+4. If K(H)=0, what are the roots/solutions?

zubka84 [21]

$H(x)=(x^2)+1\ \ \ \ and\ \ \ \ K(x)=-(x^2)+4. \\\\K(H)=-(H^2)+4=-(x^2+1)^2+4=4-(x^2+1)^2=\\\\.\ \ \ =2^2-(x^2+1)^2=(2-x^2-1)(2+x^2+1)=(1-x^2)(3+x^2)=\\\\.\ \ \ =(1-x)(1+x)(x^2-3\cdot i^2)=(1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)\\\\ K(H)=0\ \ \ \ \Leftrightarrow\ \ \ (1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)=0\\\\x=1\ \ \ \ or\ \ \ \ x=-1\ \ \ \ or\ \ \ \ x=\sqrt{3} \cdot i\ \ \ \ or\ \ \ \ x=-\sqrt{3} \cdot i\\\\Ans.\ e.$

4 0

2 years ago

30 POINTS!!! Louie is trying to find a rectangular canvas for his art project. Its diagonal must measure 23.3 inches and form a

Lisa [10]

Answer:

12 inches

Step-by-step explanation:

Given

$\theta = 31^{\circ}$

$diagonal = 23.3\ in$

Required

Determine the height of the canvas

The question is illustrated using the attached image.

Using the attachment as a point of reference, the height is calculated from

$sin \theta = \frac{opp}{hyp}$

This gives:

$sin 31^{\circ}= \frac{h}{23.3}$

Make h the subject

$h = 23.3 * sin(31^{\circ)$

$h = 23.3 * 0.5150\\$

$h = 11.9995$

$h = 12\ inches$

7 0

2 years ago

Read 2 more answers

How to write the slope intercept equation for points of (6,0) and (0,-5)?

Vadim26 [7]

Answer:

$y=\frac{5}{6} x -5$

Step-by-step explanation:

Hi there!

We are given the points (6,0) and (0, -5), and we want to write the equation of the line containing those points in slope-intercept form

Slope-intercept form can be written as y=mx+b, where m is the slope and b is the y intercept

First, we need to find the slope of the line

The formula for the slope can be written as $\frac{y_2-y_1}{x_2-x_1}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are points

We have everything we need to find the slope, but let's label the points to avoid confusion

$x_1=6\\y_1=0\\x_2=0\\y_2=-5$

Now substitute these values into the formula

m= $\frac{y_2-y_1}{x_2-x_1}$

m= $\frac{-5-0}{0-6}$

Subtract

m= $\frac{-5}{-6}$

Simplify

m= $\frac{5}{6}$

The slope of the line is 5/6

Let's plug this value into the formula for the equation of the line in slope-intercept form.

We substitute 5/6 for m in y=mx+b:
y= $\frac{5}{6}x+b$

Now we need to find b

As stated before, b is the y intercept, which is the value where the line hits the y axis. The value of x at the y intercept is 0.

One of the points we were given is actually the y intercept; that point is (0, -5); notice how the value of x in this point is 0

The value of b is the value of y in this point, which is -5 in this case.

Substitute -5 as b in the formula.

$y=\frac{5}{6} x -5$

Hope this helps!

See more on this subject here (n.b. the answer uses a different way of solving): brainly.com/question/20891204

8 0

1 year ago

Help with the below image… Thank you!

Marianna [84]

Answer: third one

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers