7. y=-3/2x+8 (3rd answer choice)
substitute
-4=-3/2(8)+b
-4=-24/2 +b
-4=-12+b
+12 both sides
8=b
so equation would be...
y=-3/2x+8 (3rd answer choice)
8. y=-5x-17 (2nd answer choice)
substitute
-2=-5(-3)+b
-2=15+b
-15 both sides
-17=b
so the equation would be...
y=-5x-17 (2nd answer choice)
check your work by substituting each (x,y) value into the final equations if you want. hope this helps :))
Using probability concepts, it is found that:
- The theoretical probability of spinning an odd number is equal to 3/5 = 0.6.
- The experimental probability of spinning an odd number is equal to 1/2 = 0.5.
- Therefore, the theoretical probability of spinning an odd number is greater than the experimental probability of spinning an odd number.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
A theoretical probability is calculated without considering experiments, and we have that 3 out of the 5 numbers(1,3,5) and are odd, hence the theoretical probability is given by:
pT = 3/5 = 0.6.
For an experimental probability, we consider the experiments. Of the 6 spins, 3 resulted in an odd number, hence the experimental probability is given by:
p = 3/6 = 1/2 = 0.5.
Therefore, the theoretical probability of spinning an odd number is greater than the experimental probability of spinning an odd number.
More can be learned about probabilities at brainly.com/question/14398287
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Answer:
4
Step-by-step explanation:
Inside a function, a certain unique input cannot ever have more than one output. All of the other tables have more than one output for only one input.
Length of AB is 18
Step-by-step explanation:
- Step 1: Find length of AB when AC = 9√3 and ∠B = 60°. Use trigonometric ratio sine.
sin 60 = opposite side/hypotenuse = 9√3/x
x = 9√3/sin 60
= 9√3/√3/2 = 9√3 × 2/√3 (∵ a ÷ b = a×1/b)
= 18
. The series is divergent. To see this, first observe that the series ∑ 1/kn for n = 1 to ∞ is divergent for any integer k ≥ 2.
Now, if we pick a large integer for k, say k > 100, then for nearly all integers n it will be true that 1 > cos(n) > 1/k. Therefore, since ∑ 1/kn is divergent, ∑ cos(n)/n must also be divergent The *summation* is divergent, but the individual terms converge to the number 0.<span>by comparison test since cosn/n <= 1/n is convergent
and 1/n is divergent by harmonic series
so the series is conditionally converget </span>