Answer:
53kg is the expected yield of lead
Explanation:
Firstly, in order to solve this question, we need to write the equation of reaction correctly. This is as follows:
PbO(s) + C(s) ---> Pb(l) + CO(g)
We proceed from here. We should get the limiting reactant but this can only be obtained by getting the number of moles of each reactant present.
The formula to use across all boards is that the number of moles is the mass of each of the reactant divided by the molar mass of each of the reactant.
For PBO, mass is 57kg = 57000g
Molar mass of PBO = 223.20g/mol
The number of moles is thus 57,000/223.2 = 255.37 moles
For carbon, mass is also 57kg = 57000g
Molar mass is 12g/mol
Number of moles of carbon = 57000/12 = 4750 moles
From the number of moles, we can see that the number of moles of Carbon is greater than that of PbO. This means that PbO is the limiting reagent.
Hence we use it to calculate percentage yield.
The number of moles of lead formed is the same of number of moles of lead oxide = 255.37 since we have mole ratio of 1 to 1
The molar mass of lead is 207.20g/mol
The mass of lead formed is = moles of lead formed * molar mass of lead = 207.20 * 255.37 = 52,912g which is approximately 53kg
Hence the expected yield is 53kg
