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Elza [17]
2 years ago
15

Which element in period 4 has the highest electronegativity

Chemistry
2 answers:
vova2212 [387]2 years ago
8 0

<span>Electronegativity is the property of an element that measures the ability of it to attract and form electron bonds. The trend in the periodic table in terms of electronegativity decreases from right to left and from top to bottom. In the case of period 4, the element with the highest electronegativity is bromine. </span>

Ad libitum [116K]2 years ago
6 0

Answer:

Bromine (Br) has the highest electronegativity.

Explanation:

Electronegativity is a measure of the tendency of an atom to attract the bonding electrons towards itself.

In general, electronegativity increases on moving from left to right across a period. Therefore, the most electronegative elements occupy the rightmost column of the periodic table. This is because, on moving across a period the atomic number increases which increases the nuclear charge on the atom. As a result, the electrons around the vicinity of such atoms feel a strong nuclear pull.

Although, noble gases occupy the last column on the right of the periodic table, they already have completely filled octets and hence in general do not exhibit electronegativity. Therefore, it is the halogen group which precede the noble gases, that are the most electronegative. Period 4, terminates with the halogen, bromine (Br) which is the most electronegative.

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An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is . The ballo
Liula [17]

The question is incomplete, here is a complete question.

An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is 13 ⁰C. The balloon is then taken outside, where the temperature is -9 ⁰C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.

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Explanation :

Charles's Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T

or,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1 = initial volume of gas = 27.8 L

V_2 = final volume of gas = ?

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T_2 = final temperature of gas = -9^oC=273+(-9)=264K

Now put all the given values in the above equation, we get:

\frac{27.8L}{286K}=\frac{V_2}{264K}

V_2=25.7L

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