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zvonat [6]
3 years ago
8

How is the energy present in the electrons passed through electron transport chain ii first used?

Chemistry
1 answer:
AVprozaik [17]3 years ago
5 0
The energy is used to pump hydrogen ions into the thylakoid space
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FIRST ANSWER = BRAINLIEST
STALIN [3.7K]

A_{r} = 24.3

The average atomic mass of X is the <em>weighted average</em> of the atomic masses of its isotopes.  

We multiply the atomic mass of each isotope by a number representing its <em>relative importance</em> (i.e., its % abundance).  

Thus,  

0.790 × 24 u = 18.96 u

0.100 × 25 u =   2.50 u

0.110 × 26 u =    <u>2.86 u</u>  

       TOTAL =  24.3   u

∴ The relative atomic mass of X is 24.3.


5 0
3 years ago
Help me with this question so I can move on from it.
fomenos

Just look it up on google kodvjkngkrefsnjkvjfrnefsjkj

7 0
3 years ago
What is the formula for chromium(iii)hydroxide
Anika [276]

Answer: Cr(OH)3

Explanation:

8 0
3 years ago
Read 2 more answers
What's the formula of mercury (I) dioxonitrate III​
steposvetlana [31]
<h2>Answer:</h2>

<h3>Hg2 ( NO2 )2</h3>

<h2>Explanation:</h2>

<h3>Formula of mercury ( 1 ) dioxonitrate 111 is Hg2 ( NO2 )2//</h3>

7 0
3 years ago
You have 180 g of radium that takes up 36 cm ^ 3 of space if you were to cut it in half and have only 90 g
Leno4ka [110]

If you were to cut the radium  in half and have only 90 g, it will take up 18 cm³.

<h3>What is density?</h3>

The density of an object is the ratio of mass to volume of object.

Density = mass/volume

volume = mass/density

at a constant density, the volume of an object is proportional to its mass.

From the question, you have 180 g of radium that takes up 36 cm ^ 3 of space if you were to cut it in half and have only 90 g, the new mass will take the following volume.

180 g = 36 cm³

90 g =  ?

= (90 x 36) / 180

= 18 cm³

Thus, if you were to cut the radium  in half and have only 90 g, it will take up 18 cm³.

Learn more about radium here: brainly.com/question/23781489

#SPJ1

6 0
2 years ago
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