-1/3(6x-15)+6x>8x-11 solve.
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Answer:
The lengths of sides of squares are 5 cm and 9 cm.
Step-by-step explanation:
Let the sides of rectangle be x and y .
Area of rectangle = Length × Breadth
Given : Area of rectangle = 45 cm².
⇒ x × y = 45
⇒ ........(1)
Two squares are constructed such that two adjacent sides of the rectangle
so squares have side x and y .
Area of square = side × side
Area of square with side x = x²
Area of square with side y = y²
Also, The combined area of the two squares is 106 cm².
⇒ x² + y² = 106
From (1) put value of x , we get,
Solving for y ,
or
on solving we get y = 5 and y = 9
Also, x can be find by putting in (1),
⇒ and ⇒
⇒ x = 9 and x = 5
Thus, lengths of sides of squares are 5 cm and 9 cm.