Answer:
C. To determine how efficient reactions are.
D. To determine how much reactant they need.
Explanation:
When you are doing a reaction, you are hoping for a percent yield to close of 100%. You make the reaction and determine how many product you obtain. If you know the percent yield of a reaction you can calculate the amount of reactant you need to obtain a determined amount of product.
Having this in mind:
A. To balance the reaction equation. false. To calculate percent yield you need to balance the reaction before. You don't use percent yield to balance the reaction
B. To determine how much product they will need. false. You determine how much product you obtain after the reaction. How much product you need is independent of percent yield
C. To determine how efficient reactions are. true. A way to determine efficience of a reaction is with percent yield. An efficient reaction has a high percent yield.
D. To determine how much reactant they need. true. If you know percent yield of a reaction you can know how many reactant you must add to obtain the amount of product you want.
Organic or inorganic is the answer
The deforestation of tropical rainforest trees to create farms and pastures, and to harvest trees for construction has increased soil erosion.
<h3>WHAT IS DEFORESTATION:</h3>
- Deforestation is the process whereby trees are cut down for commercial purposes e.g. lumbering for paper production.
- Rainforest is a vegetation characterized by trees and shrubs. However, these trees serve as soil cover and help prevent soil erosion.
This means that deforestation of tropical rainforest trees to create farms and pastures, and to harvest trees for construction has increased soil erosion
Learn more about deforestation at: brainly.com/question/11697527
Answer:
15 ml
Explanation:
Volume = mass / density.
So our answer is 15 / 3 = 15 mL
<span>C6H12O6 + O2 --> CO2 +H2O </span>
<span>In the balancede form we have: </span>
<span>C6H12O6 + 6O2 ---> 6CO2 + 6H2O </span>
<span>C -6 , H -12 and O - 18 </span>
<span>in both sides.</span>
