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2 years ago

What do chemists use percent yield calculations for in the real world?

Chemistry

1 answer:

STALIN [3.7K]2 years ago

8 0

Answer:

C. To determine how efficient reactions are.

D. To determine how much reactant they need.

Explanation:

When you are doing a reaction, you are hoping for a percent yield to close of 100%. You make the reaction and determine how many product you obtain. If you know the percent yield of a reaction you can calculate the amount of reactant you need to obtain a determined amount of product.

Having this in mind:

A. To balance the reaction equation. false. To calculate percent yield you need to balance the reaction before. You don't use percent yield to balance the reaction

B. To determine how much product they will need. false. You determine how much product you obtain after the reaction. How much product you need is independent of percent yield

C. To determine how efficient reactions are. true. A way to determine efficience of a reaction is with percent yield. An efficient reaction has a high percent yield.

D. To determine how much reactant they need. true. If you know percent yield of a reaction you can know how many reactant you must add to obtain the amount of product you want.

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The radius of an indium atom is 0.163 nm. If indium crystallizes in a face-centered unit cell, what is the length of an edge of

adoni [48]

Answer: The edge length of the unit cell is 0.461 nm

Explanation:

We are given:

Atomic radius of iridium = 0.163 nm

To calculate the edge length, we use the relation between the radius and edge length for FCC lattice:

$a=2\sqrt{2}R$

Putting values in above equation, we get:

$a=2\sqrt{2}\times 0.163=0.461nm$

Hence, the edge length of the unit cell is 0.461 nm

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2 years ago

Which of the following elements has the strongest ionization energy: Mg or Cl? Define ionization

Mila [183]

Answer:

Explanation:

The element Cl will have the strongest ionization energy from the given choices. Most non-metals have higher ionization energy compared to metals.

Ionization energy is the energy required to remove the most loosely held electron from the gaseous phase of an atom.

As you go from left to right on the periodic table, it increases progressive
From top to bottom, the ionization energy reduces significantly.
The attractive force between the protons in the nucleus and the electrons plays a very important role.
In metals, they have very large atomic radius, the attractive force on the outer electrons is very weak.
This is not the case in non-metals

5 0

3 years ago

Calculate the standard potential for the following galvanic cell: Ni(s) | Ni2+(aq) || Ag+(aq) | Ag(s) which has the overall bala

mylen [45]

Answer:

1.06 V

Explanation:

The standard reduction potentials are:

Ag^+/Ag E° = 0.7996 V

Ni^2+/Ni E° = -0.257 V

The half-cell and cell reactions for Ni | Ni^2+ || Ag^+ | Ag are

Ni → Ni^2+ + 2e- E° = 0.257 V

2Ag^+ 2e- → 2Ag E° = 0.7996 V

Ni + 2Ag^+ → Ni^2+ + 2Ag E° = 1.0566 V

To three significant figures, the standard potential for the cell is 1.06 V .

8 0

3 years ago

Mercury is a liquid meteal but it is not hard? how can we say it is a metal

NNADVOKAT [17]

What's the problem ? Hardness is not the definition of a metal. You need to expand your thinking. EVERY element is solid, liquid, and gas, over different ranges of temperature ... including all of the metals. There are only TWO elements that are liquid AT ROOM TEMPERATURE, and mercury is one of them. But on a mild day at the south pole, mercury is solid too.

7 0

3 years ago

Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. Solutes formula hydroch

matrenka [14]

Compounds which on dissolving in water gets completely dissociates into its ions are known as strong electrolytes whereas compounds which on dissolving in water gets partially dissociates into its ions are known as weak electrolytes.

Substances which gives solution on dissolving in water and do not dissociates into ions also does not conduct electric current are known as nonelectrolyte.

Hydrochloric acid, $HCl$

On adding $HCl$ (strong acid) in water, it will completely dissociates into ions ( $H^{+}$ and $Cl^{-}$ ) and thus, it is a strong electrolyte.

Sodium hydroxide, $NaOH$

On adding $NaOH$ (strong base) in water, it will completely dissociates into ions ( $Na^{+}$ and $OH^{-}$ ) and thus, it is a strong electrolyte.

Formic acid, $HCOOH$

On adding $HCOOH$ (weak acid) in water, it will partially dissociates into ions ( $H^{+}$ and $HCOO^{-}$ ) and thus, it is a weak electrolyte.

Methyl amine, $CH_3NH_2$

On adding $CH_3NH_2$ (weak base) in water, it will partially dissociates into ions ( $CH_3NH_3^{+}$ and $OH^{-}$ ) and thus, it is a weak electrolyte.

Potassium chloride, $KCl$

On adding $KCl$ in water, it will completely dissociates into ions ( $K^{+}$ and $Cl^{-}$ ) and thus, it is a strong electrolyte.

Ethanol, $C_2H_5OH$

On adding $C_2H_5OH$ in water, it will not dissociates into ions and thus, it is a nonelectrolyte.

Sucrose, $C_{12}H_{22}O_{11}$

On adding $C_{12}H_{22}O_{11}$ in water, it will not dissociates into ions and thus, it is a nonelectrolyte.

3 0

3 years ago