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3 years ago

PLEASE HELP: 60 POINTS

Chemistry

2 answers:

astra-53 [7]3 years ago

7 0

Answer:

all of they above

Explanation:

Elza [17]3 years ago

6 0

Answer:

The answer is adding a proton to the nucleus.

Explanation:

The answer is adding proton to the nucleus.

Beta decay is radioactive decay in which a beta ray and a neutrino are emitted from an atomic nucleus.

There are two types of beta decay: beta minus and beta plus.

In beta plus decay, a proton is converted to a neutron, positron and an electron neutrino, so mass number does not change.

In beta minus decay (atomic number Z is increased by one) neutron is converted to a proton and an electron and an electron antineutrino.

For example, nuclear reaction:

²⁶Na → ²⁶Mg + e⁻(electron) + ve(electron antineutrino

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3 years ago

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List emergency equipment, those are available in the laboratory?

mestny [16]

Answer:

Hands-free eyewash stations, sand bucket, fire blankets, fire extinguishers, fire alarm system and first aid kit.

Explanation:

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3 years ago

Why are the molecules of hydrocarbons nonpolar?

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3 years ago

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YALL I NEED HELP ASAP

masya89 [10]

Answer:

Yes

Explanation:

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3 years ago

Liquid octane CH3CH26CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O . Suppose

Slav-nsk [51]

Answer:

The minimum mass of octane that could be left over is 43.0 grams

Explanation:

Step 1: Data given

Mass of octane = 73.0 grams

Mass of oxygen = 105.0 grams

Molar mass octane = 114.23 g/mol

Molar mass oxygen = 32.0 g/mol

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate the number of moles

Moles = mass / molar mass

Moles octane = 73.0 grams / 114.23 g/mol

Moles octane = 0.639 moles

Moles O2 = 105.0 grams / 32.0 g/mol

Moles O2 = 3.28 moles

Step 4: Calculate the limiting reactant

For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

O2 is the limiting reactant. It will completely be consumed. (3.28 moles). There will react 3.28 / 12.5 = 0.2624 moles. There will remain 0.639 - 0.2624 = 0.3766 moles octane

Step 5: Calculate mass octane remaining

Mass octane = moles * molar mass

Mass octane = 0.3766 moles * 114.23 g/mol

Mass octane = 43.0 grams

The minimum mass of octane that could be left over is 43.0 grams

3 0

3 years ago