The molar heat of vaporization of ammonia is 23.3 kJ/mol. The molar heat of condensation of ammonia is - 23.3 kJ/mol.
The molar heat of condensation is the opposite of the molar heat of vaporization. The molar heat of vaporization of ammonia is given :
ΔH evaporation = - ΔH condensation
Therefore the molar heat of condensation of ammonia is given by:
ΔH condensation = - 23.3 kJ / mol
That's right. The molar heat of vaporization of ammonia is 23.3 kJ/mol. The molar heat of condesation of ammonia is - 23.3 kJ/mol.
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<u>Answer:</u> The molarity of solution is 
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Mass of solute (CAMP) = 0.0000000342 g
Molar mass of CAMP = 329.21 g/mol
Volume of solution = 1 L
Putting values in above equation, we get:
Hence, the molarity of solution is
My answer will be B and D
