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WINSTONCH [101]
4 years ago
13

The natural distribution of the isotopes of a hypothetical element is 60.795% at a mass of 281.99481 u, 22.122% at a mass of 283

.99570 u, and the remainder has a mass of 286.99423 u. Calculate the atomic mass of the element
Chemistry
1 answer:
fenix001 [56]4 years ago
5 0

<u>Answer:</u> The average atomic mass of the element is 283.291 amu

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

  • <u>For isotope 1:</u>

Mass of isotope 1 = 281.99481 amu

Percentage abundance of isotope 1 = 60.795 %

Fractional abundance of isotope 1 = 0.60795

  • <u>For isotope 2:</u>

Mass of isotope 2 = 283.99570 amu

Percentage abundance of isotope 2 = 22.122 %

Fractional abundance of isotope 2 = 0.22122

  • <u>For isotope 3:</u>

Mass of isotope 3 = 286.99423 amu

Percentage abundance of isotope 3 = [100 - (60.795 + 22.122)] = 17.083 %

Fractional abundance of isotope 1 = 0.17083

Putting values in equation 1, we get:

\text{Average atomic mass of element}=[(281.99481\times 0.60795)+(283.99570\times 0.22122)+(286.99423\times 0.17083)]\\\\\text{Average atomic mass of element}=283.291amu

Hence, the average atomic mass of the element is 283.291 amu

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The energy of the reactant has been higher than the energy of the product, Thus, the reaction has been an exothermic reaction.

Bond energy has been defined as the chemical energy possessed by the bonds in the chemical structure. The energy has been conserved in the chemical reaction.

<h3>Is the reaction endothermic or exothermic?</h3>

In the reaction in which bond energy of the reactant has been higher than the product, it has been an exothermic reaction.

In the reaction in which the bond energy of the product is higher than the reactant, it has been an endothermic reaction.

In the given reaction

\rm C_2H_6\;\rightarrow\;C_2H_4\;+\;H_2

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The total bond energy of the reactant has been:

\rm Reactant=6\;\times\;H-C\;bond\;+\;C-C\;bond \\Reactant=6\;\times\;413+347\;kJ/mol\\Reactant=2,825\;kJ/mol

The total bond energy of the reactant has been 2,825 kJ/mol.

The bond energies of product has been:

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The total bond energy of the product has been:

\rm Product=4\;\times\;H-C\;bond\;+\;C=C\;bond\;+\;H-H\;bond\\Product=4\;\times\;413\;+\;614\;+\;432\;kJ/mol\\Product=2,698\;kJ/mol

The total bond energy of the product has been 2,698 kJ/mol.

The energy of the reactant has been higher than the energy of the product, Thus, the reaction has been an exothermic reaction, as energy can neither be created nor be destroyed. It has been conserved in the chemical reaction.

Learn more about exothermic reaction, here:

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The addition of H2 to C5H8 yields an alkene when a Lindlar catalyst is used. Recall that the Lindlar catalysts poisons the process so that the addition do not go on to produce an alkane.

When hydroboration is carried out on the alkene, we are told that a primary alcohol was obtained. We must note that in the last step of hydroboration, water is added in an anti- Markovnikov manner to yield the primary alcohol. Hence, the starting material must be 1-pentyne as shown in the image attached.

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