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allochka39001 [22]
1 year ago
12

Find the magnitude of the sum of these two vectors: B 101 m 60.0 ° 85.0 m A​

Physics
1 answer:
slamgirl [31]1 year ago
3 0

Answer:

M= 161.1 m Deg= 32.9

Explanation:

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A 3.00 kg object is moving in the XY plane, with its x and y coordinates given by x = 5t³ !1 and y = 3t ² + 2, where x and y are
Hatshy [7]

Answer:

The net force acting on this object is 180.89 N.

Explanation:

Given that,

Mass = 3.00 kg

Coordinate of position of x= 5t^3+1

Coordinate of position of y=3t^2+2

Time = 2.00 s

We need to calculate the acceleration

a = \dfrac{d^2x}{dt^2}

For x coordinates

x=5t^3+1

On differentiate w.r.to t

\dfrac{dx}{dt}=15t^2+0

On differentiate again w.r.to t

\dfrac{d^2x}{dt^2}=30t

The acceleration in x axis at 2 sec

a = 60i

For y coordinates

y=3t^2+2

On differentiate w.r.to t

\dfrac{dy}{dt}=6t+0

On differentiate again w.r.to t

\dfrac{d^2y}{dt^2}=6

The acceleration in y axis at 2 sec

a = 6j

The acceleration is

a=60i+6j

We need to calculate the net force

F = ma

F = 3.00\times(60i+6j)

F=180i+18j

The magnitude of the force

|F|=\sqrt{(180)^2+(18)^2}

|F|=180.89\ N

Hence, The net force acting on this object is 180.89 N.

3 0
3 years ago
The shifting of the observed wavelength of light due to the motion of the source toward or away from the observer is called the
alexdok [17]

Answer:

doppler effect

Explanation:

When the relative motion of two bodies results in the wavelength becoming shorter this means that the bodies are getting closer. This is known as blue shift.

When the relative motion of two bodies results in the wavelength becoming longer this means that the bodies are getting farther. This is known as red shift.

Collectively this phenomenon is known as the Doppler effect.

7 0
2 years ago
Can someone help with this???
Rus_ich [418]

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8 0
2 years ago
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a car starts from the rest and accelerates at 9.54m/s for 6.5 seconds. what is the distance covered by the car​
uysha [10]

Answer:

= 201.53 meters

Explanation:

A car started from rest and accelerated at 9.54 m/s^2 for 6.5 seconds. How much distance was covered by the car?

Use the formula  d = \frac{at^{2} }{2} ,

where d is the distance, t is the time and "a" is the acceleration.
d=\frac{9*54*6*5^{2} }{2} = 201.53 m

3 0
2 years ago
What is the main force that must be overcome in order to push an object
My name is Ann [436]

Answer: Friction

Explanation:

Friction and the normal force would be the two initial forces to overcome.

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2 years ago
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