Question

Find the real solutions of the equation by graphing

Answer 1

Answer:

C. 0, 1.29, -0.65

Step-by-step explanation:

The real solutions of the equation $19x^3-12x^2-16x=0$  is where the graph of $y=19x^3-12x^2-16x$ intersects the x-axis.

This means that we need to graph $y=19x^3-12x^2-16x$ using a graphing software.

From the graph shown in the attachment $x=0$, $x=1.29$, and $x=-0.65$  are the  real solutions.

The correct choice is C