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Keith_Richards [23]
3 years ago
8

For the​ function, find the points on the graph at which the tangent line is horizontal. If none​ exist, state that fact. SHOW W

ORK PLEASE!

Mathematics
2 answers:
babymother [125]3 years ago
5 0

Answer:

Answer is = (√2,3+(4√2)/3), (√2 ,3- (4√2)/3.

Step-by-step explanation:

hope it helps you

Serga [27]3 years ago
3 0

9514 1404 393

Answer:

  A. (-√2, 3+(4√2)/3), (√2, 3-(4√2)/3)

Step-by-step explanation:

The tangents are horizontal where the derivative is zero. The derivative of the given function is ...

  y' = x² -2

This is zero when ...

  0 = x² -2

  2 = x²

  ±√2 = x . . . . x-values where the derivative is zero

__

The corresponding y-values are ...

  y = (1/3x² -2)x +3

  y = (1/3(2) -2)(±√2) +3 = 3 ∓ (4√2)/3

The turning points are (-√2, 3+(4√2)/3) and (√2, 3-(4√2)/3).

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Step-by-step explanation:

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Mean of 100 and a standard deviation of 15.

This means that \mu = 100, \sigma = 15

What IQ score is identified with the upper 2%?

IQ scores of at least the 100 - 2 = 98th percentile, which is X when Z has a p-value of 0.98, so X when Z = 2.054.

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