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r-ruslan [8.4K]
2 years ago
7

Can I get some help???

Mathematics
1 answer:
Schach [20]2 years ago
4 0
C. h(t) = -49t (t-2) bc you distribute to get -49t^2+98t
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Translate the phrase into a math expression. 12 less than twice a number. 2⋅n÷12 2⋅n−12 12−2⋅n 2⋅(n−12)
Andre45 [30]

Answer:

2n - 12 \: is \: the \: math \: expression

8 0
3 years ago
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Please please help
777dan777 [17]

Step-by-step explanation:

Statement. Reason

→ 9(x-6)+41 = 75. Transposing the like terms.

→ 9(x-6) = 75 - 41 Performing subtraction of the term in RHS

→ 9(x-6) = 34 Performing multiplication in LHS.

→ 9x - 54 = 34 Distributive property

→ 9x = 34 + 54 Performing addition of the term in RHS.

→ 9x = 88. Now, transpose 9 from LHS to RHS , it's arthmetic operator will get changed.

→ x = 88/9

6 0
2 years ago
DOOOO NOTTT SKIPPPPPPP
Shalnov [3]
1st one RS=DE,
second one T=F,
last one R=D
7 0
3 years ago
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Daniel got a traffic citation. He had the option of paying 30% of his fine for traffic school. If traffic school cost $240, how
White raven [17]
30% of the fine is $240

Let x = fine
.3x = 240 \\ x = 240  \div .3 \\ x = 800
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5 0
3 years ago
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A data scientist studying a manufacturing process classifies each item produced by the process as either Poor, Acceptable, or Ex
Genrish500 [490]

Answer:

0.214 ; 0.064 ; 0.3859 ; 0.9966 ; 0.135

Step-by-step explanation:

Given the distribution :

Poor ___ Acceptable ____ Excellent

0.25 _____ 0.6 _________ 0.15

The data scientist receives three items produced by the manufacturing process.

Find the chance that:

a. all of items are Acceptable

0.6 * 0.6 * 0.6 = 0.6^3 = 0.214

b. none of the items is Acceptable

P(not acceptable) = 1 - p(acceptable) = 1 - 0.6 = 0.4

0.4 * 0.4 * 0.4 = 0.4^3 = 0.064

c. at least one of the items is Excellent

P(atleast one) = 1 - P(none)

P(not excellent) = 1 - 0.15 = 0.85

P(none is excellent) = 0.85^3 = 0.614125

Hence,

P(atleast one is excellent) = 1 - 0.614125 = 0.3859

d. not all of the items are Excellent

P(not all) = 1 - p(All)

P(all excellent) = 0.15^3 = 0.003375

P(not all are excellent) = 1 - 0.003375 = 0.9966

e. there is one item of each class:

P(poor) * p(acceptable) * p(excellent) * (number of classes)!

0.25 * 0.6 * 0.15 * 3!

= 0.135

3 0
3 years ago
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