it took to long for you to rkgnhyh2gnb 45kljhnt4kjl ht3kltnhkj3rgn4tn2t4kb ktnhkjthk6l
Imagine a right triangle where a and b are the legs and c is the hypothenuse.
Pitagora: a²+b²=c²
Divide by c
(a/c)²+(b/c)²=1
But a/c=sin(B) and b/c=cos(B)
Thus sin² + cos² = 1
Answer:
A, D, E
Step-by-step explanation:
for a function in its inverse, the domain and range are switched.
