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NikAS [45]
3 years ago
7

What is the x-coordinate of the midpoint of the segment whose endpoints are (2, 3) and (-5, 5)?

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
7 0

Answer:

(-3/4, 4)

Step-by-step explaination:

add 2 and -5 then divide them by two and get

-1/2

then add 3 and 5 divide them by two and get

11/2

But as long as you remember that you're averaging the two points' x- and y-values, you'll do fine. It won't matter which point you pick to be the "first" point you plug in. Just make sure that you're adding an x to an x, and a y to a y.

so therefore the answer is (-3/4, 4)

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3. A line goes through the points (3,4) and (-3,6).
Galina-37 [17]

Answer:

Part a) The slope is m=-\frac{1}{3}

Part b) The equation in point slope form is y-4=-\frac{1}{3}(x-3)

Part c) The equation in slope-intercept form is y=-\frac{1}{3}x+5

Step-by-step explanation:

we have the points (3,4) and (-3,6)

Part a) What is the slope of the line?

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the given points

m=\frac{6-4}{-3-3}

m=\frac{2}{-6}

m=-\frac{1}{3}

Part b) Write the equation of the line in point-slope form

y-y1=m(x-x1)

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m=-\frac{1}{3}

point\ (3,4)

substitute

y-4=-\frac{1}{3}(x-3)  ---> equation in point slope form

Part c) Write the equation of the line in slope-intercept form

y=mx+b

we have

y-4=-\frac{1}{3}(x-3)

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distribute right side

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Adds 4 both sides

y=-\frac{1}{3}x+1+4

y=-\frac{1}{3}x+5 ---> equation in slope intercept form

7 0
3 years ago
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