Answer:
The yield is 20 %.
Explanation:
Mg + 2 HCl → MgCl2 + H2
(12 g Mg) / (24.30506 g Mg/mol) x (1 mol H2 / 1 mol Mg) x (2.015894 g H2/mol) = 0.9953 g H2.
(0.2 g) / (0.9953 g) = 0.20 = 20% yield
Answer:
1.36x10^10L
Explanation:
Step 1:
Determination of the mole of fluorine that contains 3.66x10^32 molecules. This is shown below:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This implies that 1 mole of fluorine also contains 6.02x10^23 molecules.
Now if 1 mole of fluorine contains 6.02x10^23 molecules,
Therefore, Xmol of fluorine will contain 3.66x10^32 molecules i.e
Xmol of fluorine = 3.66x10^32/6.02x10^23
Xmol of fluorine = 6.08x10^8 moles
Step 2:
Determination of the volume occupied by 6.08x10^8 moles of fluorine.
1 mole of any gas occupy 22.4L at stp. This means that 1 mole of fluorine also occupy 22.4L at stp.
Now if 1 mole of fluorine occupies 22.4L at stp,
Then 6.08x10^8 moles of fluorine will occupy = 6.08x10^8 x 22.4 = 1.36x10^10L
2 NaCl --------> 2 Na + Cl₂
2 mol * 23 g Na = 46 g
2*35,5 g Cl = 71
46 g Na --------- 71 g Cl₂
460 g Na -------- ?
mass ( Cl₂) = 460 . 71 / 46
Mass (Cl₂) = 32660 / 46
m= 710 g of Cl₂
<span>hope thips helps</span>
Answer:
Kc = 3.90
Explanation:
CO reacts with 
to form 
and 
. balanced reaction is:
No. of moles of CO = 0.800 mol
No. of moles of = 2.40 mol
Volume = 8.00 L
Concentration = 
Concentration of CO = 
Concentration of = 
Initial 0.100 0.300 0 0
equi. 0.100 -x 0.300 - 3x x x
It is given that,
at equilibrium 
= 0.309/8.00 = 0.0386 M
So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M
At equilibrium = 0.300 - 0.0386 × 3 = 0.184 M
At equilibrium = 0.0386 M
![Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_2O%5D%5BCH_4%5D%7D%7B%5BCO%5D%5BH_2%5D%5E3%7D)
