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3 years ago

All the distances are measured from the........ of spherical mirror

Chemistry

1 answer:

slega [8]3 years ago

8 0

Answer:

All distances are measured from pole of the mirror

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a chemical change results in the formation of one or more new substances

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4 years ago

On 100 corex

Julli [10]

Answer:

P(total) = 164 mmHg

Explanation:

Given data:

Partial pressure of helium = 77 mmHg

Partial pressure of nitrogen = 87 mmHg

Total pressure of flask = ?

Solution:

According to Dalton law of partial pressure,

The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.

Mathematical expression:

P(total) = P₁ + P₂ + P₃+ ............+Pₙ

Now we will solve this problem by using this law.

P(total) = P(He) + P(N₂)

P(total) = 77 mmHg + 87 mmHg

P(total) = 164 mmHg

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3 years ago

Indicate the changes (increases, decreases, does not change) in its volume when the pressure undergoes the following changes at

Inga [223]

The question is missing information. Here is the complete question.

A gas at a pressure of 2.0 atm is in a closed container. Indicate the changes (if any) in its volume when the pressure undergoes the following changes at constant temperature and constant amount of gas. Match the words in the left with the column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.

1. The pressure increases to 6.0 atm. The volume ________

2. The pressure drops to 0.40 atm. The volume _________

3. The pressure remains at 2.0 atm. The volume _________

Answer: 1. Decreases

2. Increases

3. Does not change

Explanation: According to the Ideal Gas Law, Pressure, Volume and Temperature of an ideal gas is related, as the following: PV = nRT.

In this case, since temperature (T) and amount of gas (n) are constant, the Boyle's Law can be used.

The law states that the volume of a given gas, under the conditios of temperature and amount of it are constant, is inversely proportional to the applied pressure: P₁.V₁ = P₂.V₂

For case 1.)

Initial P (P₁) = 2

Initial V (V₁) = V

Final P (P₂) = 6

P₁.V₁ = P₂.V₂

2.V = 6.V₂

V₂ = 1/3V

When the pressure increases to 6 atm, volume decreases by 1/3.

For case 2.)

P₁ = 2

V₁ = V

P₂ = 0.4

2.V = 0.4V₂

V₂ = 5V

When pressure drops to 0.4 atm, volume increases by 5.

For case 3.)

Since there are no change in the pressure, the volume is the same from the beginning, so does not change.

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3 years ago

BF needed Near raleigh

Studentka2010 [4]

Answer:

what

Explanation:

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3 years ago

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All the distances are measured from the........ of spherical mirror​

All the distances are measured from the........ of spherical mirror