3-25200 m
4- 0.0023 cl
5-
6- 23 mm
7-4500mm
8-450000ml
9-0.45kg
10-
Sorry I couldn’t get them all but there is most of the answers
The initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.
<em>"Your question is not complete, it seems to be missing the following information;"</em>
the specific heat capacity of the metal is 0.45 J/g⁰C.
The given parameters;
- <em>mass of water, </em>
<em> = 45 g</em> - <em>final temperature of the water, </em>
<em> = 22 ⁰C</em> - <em>mass of the metal, m = 8.5 g</em>
- <em>initial temperature of the metal, t = 82 ⁰C.</em>
- <em>specific heat capacity of the metal, c = 0.45 J/g⁰C.</em>
The initial temperature of the water will be calculated by applying the principle of conservation of energy;
<em>heat gained by water = heat lost by metal</em>


where;
<em>is the specific heat capacity of the water = 4.184 J/g⁰C.</em>
<em />
<em>Substitute the given values;</em>
45 x 4.184 x (22 - t) = 8.5 x 0.45 x (85 - 22)
4142.16 - 188.28t = 240.98
188.28t = 4142.16 - 240.98
188.28t = 3901.18

Thus, the initial temperature of the water that resulted in the final temperature of the water-metal mixture is 20.7 ⁰C.
Learn more here:brainly.com/question/15345295
6.5 is subtracted from each number.
9 - 6.5 = 2.5
2.5 - 6.5 = -4
-4 - 6.5 = -10.5
-10.5 - 6.5 = -17
or you could think of adding -6.5 to everything if that is easier for you to picture.
Destornilladores, alicates de corte diagonal, alicates de punta fina, alicates de bomba ajustable y cinta métrica con punta magnética
<span> calorimeter. 4 c6h5nh2(l) + 35 o2(g) → 24 co2(g) + 14 h2o(g) + 4 no2(g)</span>