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mash [69]
4 years ago
14

Calculate the solubility of cux(ksp=[cu2+][x2−]=1.27×10−36) in a solution that is 0.190 m in nacn.

Chemistry
2 answers:
nataly862011 [7]4 years ago
8 0

if you have 1.27*10^-36= [Cu2+][X2-] then you can set both those values equal to x because they're stoichimetrically equal.

1.27*10^-36=x^2

Take the square root of both sides.

1.13*10^-18=x

That would be your solubility.

Paha777 [63]4 years ago
4 0

Answer:

Solubility = 2.58×10^-18M

Explanation:

Ksp= (Cu^2+)(x)

X=( 1.27x10^-36)/0.190

X= 6.68×10^-36moles/litre

Solubility = Sqrt(6.68×10^-36)

Solubility = 2.58×10^-18M

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Answer:

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a)

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H_2SO_4(aq) + NaOH(aq) \rightarrow Na_2SO_4 (aq) + H_2O (l)

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Ba(OH)2 + 2HF\rightarrow BaF_2 + 2H_2O

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Answer:

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Explanation:

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