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3 years ago

13

Hnhhhhhhhhhhhhhhhhhhh

1 answer:

nignag [31]3 years ago

8 0

Answer:

Step-by-step explanation:

First let's find the circle without the gray area. We would have:

$\pi r^2=\pi 36^2=\pi1296$

Next let's find the area of the circle with the gray area. We would have:

$\pi r^2=\pi50^2=\pi2500$

Now we subtract and get:

$(2500-1296)\pi=\boxed{1204\pi}$

HOPE THIS HELPS

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The difference of d minus 3 divided by 2?

Allisa [31]

$\text{Hey there!}$

$\text{What is the difference of d minus 3 divided by 2?}\\\\\text{Difference means subtract/subtraction}\\\\\text{Minus would also be subtraction}\\\\\text{Divided by is division}\\\\\text{d would be the start of the problem}\\\\\text{the 3 divided by 2 would be on the right side ( the second part of the equation)}\\\\\boxed{\boxed{\bf{\ Answer:: d-\dfrac{3}2{}}}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day}\\\\\\\frak{LoveYourselfFirst:)}$

6 0

3 years ago

You plant a garden in the shape of a triangle as shown in the figure. What is the perimeter of the garden? Find the values of x

Vadim26 [7]

Answer:

x = 42°

y = 69°

Step-by-step explanation:

From the picture attached,

Given triangle is an isosceles triangle.

Therefore, two sides will be equal and measure 8 yd.

Measure of 3rd side of the triangle = 6 yd

Perimeter of the garden = 8 + 8 + 6

= 22 yd

In an isosceles triangle, opposite angles of the equal sides will be equal.

Therefore, y = 69°

By the property of interior angles of a triangle,

x° + y° + 69° = 180°

x° + 69° + 69° = 180°

x = 180 - 138

x = 42°

7 0

3 years ago

HELPP!!what is the answer to this picture above^

nasty-shy [4]

Answer:

$\fbox{ \fbox { \sf{Distance = \sf{15 \: units}}}}$

${ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}$

Step-by-step explanation:

$\star{ \: \sf { \: Let \: the \: points \: be \: A \: and \: B}}$

$\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}$

$\underline{ \underline{ \tt{Finding \: the \: distance}}}$

$\boxed{ \sf{Distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(18 - 6)}^{2} + {(15 - 6)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(12)}^{2} + {(9)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{144 + 81}}}$

$\mapsto{ \sf{Distance = \sqrt{225} }}$

$\mapsto{ \sf{Distance = \sqrt{ {15}^{2} } }}$

$\mapsto{ \boxed{\sf{Distance = 15 \: units}}}$

$\underline{ \underline {\tt{Finding \: the \: Midpoint}}}$

$\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2} \: , \: \frac{6 + 15}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{24}{2} \: , \: \frac{21}{2} )}}$

$\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}$

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

3 0

3 years ago

The table shows the results of a survey of seventh-grade students in the lunch-line

Anni [7]

Answer:

D

Look at the picture. :)

5 0

3 years ago

What is the vertex for the following quadratic?<br> f(x)= 2x^2-12x+16

LenaWriter [7]

Answer:

(3, -2)

Step-by-step explanation:

To find the vertex, put the equation into vertex form by completing the square

2(x^2 - 6x) + 16 [pulling out the 2]

2(x^2 - 6x + 9) - 18 + 16 [completing the square, you subtracted 2*9 = 18 so you also add 18]

2(x - 3)^2 - 2 [simplify the equation]

vertex is (3, -2)

7 0

3 years ago