Explanation:
Given parameters
Period = 2.34minutes
Unknown:
Frequency of the oscillator = ?
Solution:
Frequency is the number of waves that passes through a point at a given time. It is the inverse of period which is the time it takes for a wave to pass through a medium:
F = 
F is the frequency
T is the period
To solve this, convert the period to seconds:
2.34minutes to seconds:
1 min = 60seconds
2.34 = 60 x 2.34 = 140.4s
F =
= 0.007hz or 0.007s⁻¹
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The moles of the gas in the sample is 0.391 moles
calculation
by use of ideal gas equation, that is Pv=nRT
where n is number of moles
P(pressure)= 660 mmhg
R(gas constant) = 62.364 l.mmhg/mol.K
T(temperature)= 25 +273 = 298 k
by making n the subject of the formula
n= Pv/ RT
n is therefore= (660mm hg x11 L)/( 62.364 L.mmhg/mol.k x298 K) = 0.391 moles
Answer: The correct option is A,
--> a.) Transition metals have partially filled d subshells.
Explanation:
Transition elements are all metals of economic importance. They are found in the d- lock of the periodic table between group 2 and 3. They occupy three rows, with ten elements in each row. The term 'transition metals' refers only to an element which has PARTIALLY filled d orbitals. Typical example of transition metals include iron (Fe).
They have partially filled 3d orbitals which are responsible for the special properties of the metals. These include:
--> Physical properties: the transition metals have high boiling and melting points. They are hard, dense and lustrous. They are also good conductors of heat and electricity.
--> Chemical reactivity: In the s- block and p-block, the chemical properties of the elements in the same period vary, often quite markedly, from left to right. This does not happen with the transition metals because electrons are added progressively to the inner d-orbitals.
--> Variable oxidation states: they have variable oxidation states because 3d electrons are available for bond formation.
<u>Explanation:</u>
Unit is defined as the quantity that is used as a standard for measurement.
S.I. unit of mass of kilograms. Other units in which mass of a substance can be measured are grams, milligrams, etc...
All these units are inter convertible.
The conversion factor used is:

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The conversion factor used is:

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Answer:
The volume of cupboard is 2.0043 m³.
Explanation:
Given data:
width of cupboard = 1.31 m
length of cupboard = 0.9 m
height of cupboard = 1.70 m
Volume = ?
Solution:
Volume = length × width × height
Volume = 0.9 m × 1.31 m × 1.70 m
Volume = 2.0043 m³
The volume of cupboard is 2.0043 m³.