3. Cl₂ + 2KI --> 2KCl + I₂
Cl = 2 Cl = 2
K = 2 K = 2
I = 2 I = 2
4. 2NaCl --> 2Na + Cl₂
Na = 2 Na = 2
Cl = 2 Cl = 2
5. 4Na + O₂ --> 2Na₂O
Na = 4 Na = 4
O = 2 O = 2
6. 2Na + 2HCl --> H₂ + 2NaCl
Na = 2 Na = 2
H = 2 H = 2
Cl = 2 Cl = 2
7. 2K + Cl₂ --> 2KCl
K = 2 K = 2
Cl = 2 Cl = 2
The specific heat in, J /g °C of copper is 0.386J/g°C
HOW TO CALCULATE SPECIFIC HEAT CAPACITY OF A SUBSTANCE:
- The specific capacity of a substance can be calculated using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat absorbed or released (J)
m = mass of substance (g)
∆T = change in temperature (°C)
c = specific heat capacity (J/g°C)
For a colorimeter, the following equation applies:
m.c.∆T (water) = - m.c.∆T (metal)
m = 50g
c = 4.184 J/g°C
∆T = 29.2 - 26°C = 3.2°C
m = 70g
c = ?
∆T = 29.2 - 54°C = -24.8°C
m.c.∆T (water) = - m.c.∆T (metal)
50 × 4.184 × 3.2 = -(70 × c × -24.8)
669.44 = 1736c
c = 669.44 ÷ 1736
c = 0.386J/g°C
Therefore, the specific heat in, J /g °C of copper is 0.386J/g°C
Learn more at: brainly.com/question/16787162?referrer=searchResults
Answer: Heat of melting s = 333 kJ/kg and heat of vaporisation r= 2160 kJ/kg
Explanation:
Answer: 2 AgNO3(aq) + NiCl2(aq) ⇒ 2 AgCl(s) + Ni(NO3)2 (aq)
Explanation:
