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Mrac [35]
3 years ago
10

HELP! 10 points rewarded, plus, best answer gets BAINLIEST!!

Chemistry
1 answer:
kotegsom [21]3 years ago
6 0

Answer:

4.08 grams

Explanation:

Essentially, we're looking for the mass of HCl that "matches" 3.26 grams of magnesium hydroxide.

First, convert 3.26 grams of Mg(OH)_2 into moles by dividing by the molar mass. The molar mass of Mg(OH)_2 is 24.3 + 16 * 2 + 1 * 2 = 58.3 g/mol. So, 3.26 grams is equal to:

3.26 g ÷ 58.3 g/mol = 0.0559 mol Mg(OH)_2

Notice that from the chemical equation, magnesium hydroxide and hydrochloric acid (HCl) have a ratio of 1 to 2. In other words, for every 0.0559 moles of Mg(OH)_2, there are 0.0559 * 2 = 0.112 moles of HCl.

Finally, convert moles of HCl to grams by multiplying 0.112 by the molar mass, which is 1 + 35.45 = 36.45 g/mol:

0.112 mol HCl * 36.45 g/mol = 4.08 g HCl

The answer is thus 4.08 grams.

<em>~ an aesthetics lover</em>

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statuscvo [17]

Answer:

17.1 mol

Explanation:

(8.68g/mL * 125 mL) = 1085 g

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3 years ago
according to the kinetic molecular theory the pressure exerted by a sample of gas at constats volume doubles when the absolute t
ozzi

Answer: gas molecules will hit the container walls more frequently and with greater force

Explanation:

According to the postulates of  kinetic molecular theory:

1. The pressure exerted by a gas in a container results from collisions between the gas molecules and the container walls.

2. The average kinetic energy of the gas molecules is proportional to the kelvin temperature of the gas.

When the temperature is increased, so the average kinetic energy and the rms speed also increase. This means that the gas molecules will hit the container walls more frequently and with greater force because they are all moving faster. This increase the pressure.

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3 years ago
If iodine-131 has a half-life of 8 days, how much of a 64.0 g sample of iodine-131 will remain after 32 day?
Mariulka [41]

Answer:

4 g OF IODINE-131 WILL REMAIN AFTER 32 DAYS.

Explanation:

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Elapsed time (t) = 32 days

Mass remaining (Nt) = ?

Using the half life equation we can obtain the mass remaining (Nt)

Nt = No (1/2) ^t/t1/2

Substituting the values, we have;

Nt = 64 * ( 1/2 ) ^32/8

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Nt = 64 * 0.0625

Nt = 4 g

So therefore, 4 g of the iodine-131 sample will remain after 32 days with its half life of 8 days.

8 0
3 years ago
(20 POINTS) HELP... If you add an unknown liquid to a solution that has a pH of 5, and the pH of the new mixture goes down to 3,
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D

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n(H₂)=m(H₂)/M(H₂)
n(H₂)=5g/2.0g/mol=2.5 mol

n(O₂)=m(O₂)/M(O₂)
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2.5 : 1.25 = 2 : 1

n(H₂O)=n(H₂)=2n(O₂)=2.5 mol

m(H₂O)=n(H₂O)M(H₂O)

m(H₂O)=2.5mol*18.0g/mol=45.0 g
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