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2 years ago

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In an engine, an almost ideal gas is compressed adiabatically to half its volume. In doing so, 2820 J of work is done on the gas

.
Required:
a. How much heat flows into or out of the gas?
b. What is the change in internal energy of the gas?
c. Does its temperature rise or fall?

1 answer:

Dmitry_Shevchenko [17]2 years ago

3 0

Answer:

$Q=0$
$U=2820$
Energy increases

Explanation:

From the question we are told that

Work done $W=2820$

a)Generally the heat flow for an adiabatic process is 0 (zero)

$Q= U + W =>0$

$Q=0$

b)Generally Change in internal energy of gas is mathematically given by

Since $W=-2820J$

Therefore

$U=2820$

Giving

$Q= 2820 -2820$

$Q=O$

c)With increases in internal energy brings increase in temperature

Therefore

Energy increases

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Debora [2.8K]

Answer:

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Corrected question;

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