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3 years ago

A boat moves up and down as water waves pass under the boat. If the amplitude of the wave gets bigger, then

Physics

2 answers:

xeze [42]3 years ago

7 0

The anwser is A or D

garik1379 [7]3 years ago

3 0

Answer: The Boat will rise

Explanation: Because high amplitude means high in heights.

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An earthquake releases two types of traveling seismic waves, called transverse and longitudinal waves. The average speed of the

Norma-Jean [14]

Answer:

1083.173 km

Explanation:

Speed of longitudinal waves = 9.1 km/s

Speed of transverse waves = 5.7 km/s

Time taken by the longitudinal wave is t

Time taken by the transverse wave is t+71

Distance = Speed × Time

Distance traveled by the longitudinal wave

$\text{Distance}=9.1t$

Distance traveled by the transverse wave

$\text{Distance}=5.7(t+71)$

Since both distances are equal

$9.1t=5.7(t+71)\\\Rightarrow 9.1t-5.7t=404.7\\\Rightarrow 3.4t=404.7\\\Rightarrow t=\frac{404.7}{3.4}=119.03\ s$

The time taken by the longitudinal wave is 119.03 seconds

Distance traveled by the longitudinal wave

$9.1t=9.1\times 119.03=1083.173\ km$

The earthquake is 1083.173 km away

7 0

4 years ago

In a circus act, a uniform board (length 3.00 m, mass 25.0 kg ) is suspended from a bungie-type rope at one end, and the other e

tester [92]

Answer:

Force of Rope = 122.5 N

Force of Rope = 480.2N

Explanation:

given data

length = 3.00 m

mass = 25.0 kg

clown mass = 79.0 kg

angle = 30°

solution

we get here Force of Rope on with and without Clown that is

case (1) Without Clown

pivot would be on the concrete pillar so Force of Rope will be

Force of Rope × 3m = (25kg)×(9.8ms²)×(1.5m)

solve it and we get

Force of Rope = 122.5 N

and

case (2) With Clown

so here pivot is still on concrete pillar and clown is standing on the board middle and above the centre of mass so Force of Rope will be

Force of Rope × 3m = (25kg+73kg)×(9.8ms²)×(1.5m)

solve it and we get

Force of Rope = 480.2N

4 0

4 years ago

During most of its lifetime, s star maintains an equilibrium size in which the inward force of gravity on each atom is balanced

frez [133]

Answer:

$r_f=137493m$

$v=8638940m/s$

Explanation:

During this process the mass $M=2\times10^{30}Kg$ will be considered constant. We start from a radius $r_i=7\times10^8m$ and a period $T_i=30\ days=(30)(24)(60)(60)s=2592000s$ . The final period is $T_f=0.1s$ .

Angular momentum <em>L</em> is conserved in this process. We can use the formula $L=I\omega$ , where I is the momentum of inertia (which for a solid sphere is $I=\frac{2mr^2}{5}$ ) and $\omega=\frac{2\pi }{T}$ is the angular velocity, so we can write the star's angular momentum as: