A train accelerates from rest and covers a distance of 600m in 20s. What is the train's speed at the end of 20s? What is the fin
1 answer:
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Answer:
(a). The change in the average kinetic energy per atom is .
(b). The change in vertical position is 2413 m.
Explanation:
Given that,
Mass = 40.0 u
The increased temperature from 286 K to 362 K.
(a). We need to calculate the change in the average kinetic energy per atom
Using formula of kinetic energy
Put the value into the formula
(b). The change in potential energy of the container due to change in the vertical position
We need to calculate the change in vertical position
Using formula of potential energy
Hence, (a). The change in the average kinetic energy per atom is .
(b). The change in vertical position is 2413 m.
Answer:
Deceleration of 0.075m/s²
Explanation:
Given parameters:
Initial velocity = 5m/s
Time = 40s
Final velocity = 2m/s
Unknown:
The jogger's acceleration = ?
Solution:
To solve this problem, we use;
a =
a is the acceleration
v is the final velocity
u is the initial velocity
t is the time taken
a = = - 0.075m/s²
Answer:
The answer is "1.5625".
Explanation:
Please find the complete question with its solution file in the attachment.
