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Law Incorporation [45]
3 years ago
5

A train accelerates from rest and covers a distance of 600m in 20s. What is the train's speed at the end of 20s? What is the fin

al velocity of the train after 20s?
Physics
1 answer:
Allushta [10]3 years ago
6 0

Answer:

v = 60 m/s

final velocity after 20 seconds depends on how long it continues to accelerate after 20 seconds. Also we do not know the direction to complete the velocity requirements of a scalar value and direction component.

Explanation:

If we assume that the acceleration is constant

d = ½at² = ½(Δv/t)t² = ½Δvt = ½(v - 0)t = ½vt

v = 2d/t

v = 2(600)/20 = 60m/s

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Answer:

-1.43 m/s relative to the shore

Explanation:

Total momentum must be conserved before and after the run. Since they were both stationary before, their total speed, and momentum, is 0, so is the total momentum after the run off:

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Answer:

m₁ / m₂ = 1.3

Explanation:

We can work this problem with the moment, the system is formed by the two particles

The moment is conserved, to simulate the system the particles initially move with a moment and suppose a shock where the particular that, without speed, this determines that if you center, you should be stationary, which creates a moment equal to zero

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Another way to solve this exercise is to use the mass center relationship

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We derive from time

   Vcm = 1/M   (m₁ v₁ + m₂v₂)

As they say the velocity of the center of zero masses

    0 = 1/M   (m₁ v₁ + m₂v₂)

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    m₁ / m₂ = -v₂ / v₁

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