Can someone help me wth this

A bag contains three marbles, eight blue marbles and nine red marbles. If the marbles are picked at random, what is the probabil

Phoenix [80]

The probability of obtaining two blue marbles without replacement is equal to 0.15.

We are given that:

The number of yellow marbles = 3

Number of red marbles = 9

Number of Blue marbles = 8

Total marbles = 3 + 9 + 8

Total marbles = 20

Now, we have to calculate the probability of obtaining two blue marbles without replacement.

The probability will be:

P( obtaining two blue marbles without replacement ) = 8 / 20 × 7 / 19

P( obtaining two blue marbles without replacement ) = 56 / 380

P( obtaining two blue marbles without replacement ) = 0.15

Therefore, the probability of obtaining two blue marbles without replacement is equal to 0.15.

Learn more about probability here:

brainly.com/question/24756209

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5 0

2 years ago

Which equation could have been used to create this function table?

Ierofanga [76]

It would be c. y = x because if you plug in the numbers, it would be true

8 0

3 years ago

Read 2 more answers

40 POINTS Worth

Verizon [17]

Is this a right triangle or not? If it's a right triangle, you could use the Pythagorean Theorem to find the length of the 3rd side, which would be the hypotenuse. Thus, 14^2 + 4^2 = c^2, where c is the length of the hypot.

Then 196 + 16 = 212, and this is c^2. Then c, the length of the hypotenuse, is sqrt 212, or approx. 14.6 inches.

This does not agree with any of the four possible answers. Thus, you must look at each of these possible answers and eliminate any that could not be correct.

for example: if you take 10 inches and add 4 inches, you get 14 inches. The result would not be a triangle, but rather a straight line.

Check out the others similarly.

5 0

3 years ago

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What is BE ?<br> Please explain it in full dont just give me an answer

posledela

There are two methods to solve this problem. One of them is the typical method and the other one is the short-cut. I will explain the shortcut

Short-cut:
This method is quick and easy, and works with ALL triangles, which is why I suggest you use this. You make proportions. Since the triangles are similar, we can use CPCTC. Thereafter,
$\frac{AD}{CE}= \frac{DB}{EB}$

Now, you just need to identify the terms, substitute, and solve for the unknown, which would be k.

$\frac{12}{3} = \frac{k+5}{k-7} \\ 12(k-7)=3(k+5) \\ 12k-84=3k+15 \\ 9k=84+15 \\ 9k=99 \\ k=11$ [/tex]

So we found k, but it is asking for BE. Therefore, plug in the value of k, which is 11, into the expression for BE, which is k-7.

BE=K-7
k=11
BE=11-7
BE=4

Your answer is 4.

5 0

3 years ago

Hi! I have a question and I don't understand it's answer. Could you help me?It's in the attachment below.

Paladinen [302]

To solve this question, we just need to evaluate our set of points in the standard form equation of a Hyperbola, and find the coefficients. This will give to us the equation for our Hyperbola. The standard form is

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

Let's start with the easier points, the x-intercepts (5, 0) and (-1, 0).

Since this hyperbola has two x-intercepts, we're dealing with a horizontal hyperbola, and the center is the midpoint between the x-intercepts.

$\begin{gathered} \bar{x}=\frac{x_1+x_2}{2}=\frac{-1+5}{2}=2 \\ \bar{y}=\frac{y_1+y_2}{2}=\frac{0+0}{2}=0 \end{gathered}$

The center coordinates are (2, 0), then, our equation is

$\frac{(x-2)^2}{a^2}-\frac{y^2}{b^2}=1$

To find the missing coefficients, we can just substitute the remaining points and solve the system for a and b. Our final equation is

$\frac{(x-2)^2}{9^{}}-\frac{y^2}{4}^{}=1$

6 0

1 year ago