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vichka [17]
2 years ago
8

Can someone help me wth this

Mathematics
1 answer:
alukav5142 [94]2 years ago
7 0
The answer for Y=3x or graph four

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Can any one help me on these two PleaseI
igor_vitrenko [27]

Answer:

This is what i get

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the surface area of the box if it is scaled up by the factor of 10 and the surface area is 16in
algol [13]
If each linear dimension is scaled by a factor of 10, then the area is scaled by a factor of 100. This is because 10^2 = 10*10 = 100. Consider a 3x3 square with area of 9. If we scaled the square by a linear factor of 10 then it's now a 30x30 square with area 900. The ratio of those two areas is 900/9 = 100. This example shows how the area is 100 times larger.

Going back to the problem at hand, we have the initial surface area of 16 square inches. The box is scaled up so that each dimension is 10 times larger, so the new surface area is 100 times what it used to be

New surface area = 100*(old surface area)
new surface area = 100*16
new surface area = 1600

Final Answer: 1600 square inches

3 0
3 years ago
What is the derivative of this
skelet666 [1.2K]
\bf r(x)=\cfrac{3x-2}{2x+5}\implies \cfrac{dr}{dx}=\stackrel{quotient~rule}{\cfrac{3(2x+5)~~-~~(3x-2)2}{(2x+5)^2}}
\\\\\\
\cfrac{dr}{dx}=\cfrac{\underline{6x}+15\underline{-6x}+4}{(2x+5)^2}\implies \cfrac{dr}{dx}=\cfrac{19}{(2x+5)^2}
7 0
3 years ago
According to the graph, the system of linear equations has how many solutions?
slamgirl [31]

no solutions → C

The 2 given lines are parallel and never intersect thus no solution


8 0
3 years ago
Read 2 more answers
If $15,000 is invested at an interest rate of 2% per year, compounded semiannually, find the value of the investment after the g
Gennadij [26K]

Answer:

Step-by-step explanation:

If $10,000 is invested at an interest rate of 2% per year, compounded semiannually, find the value of the investment after the given number of years. (Round your answers to the nearest cent.)

a)6 years

b)12 years

c)18 years

***

compound interest formula: A=P(1+r/n)^nt, P=initial investment, r=interest rate, n=number of compounding periods per year, A=amt after t-years.

For given problem:

P=10000

r=.02

n=2

t=6, 12, 18

..

A(6)=10000(1+.02/2)^2*6

A(6)=10000(1.01)^12=11,268.25

A(12)=10000(1.01)^24=12,697.35

A(18)=10000(1.01)^36=14,307.69

3 0
3 years ago
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