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jeka94
3 years ago
12

I’ll give u a kiss if u help me with this ASAP PLZZZ;) with an explanation too plzzz

Mathematics
1 answer:
Dvinal [7]3 years ago
8 0
Can i get a kiss??? x#*||~~
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Infiniti sells 8 different models of cars, with 5 different trim levels and 5 color choices. What is the total amount of options
solniwko [45]

Answer:

200

Step-by-step explanation:

Infiniti sells 8 different models of cars, with 5 different trim levels and 5 color choices.

Now, 8 different models of cars with 5 different trim levels have (8 × 5) = 40 choices.

Similarly, with  8 different models of cars, with 5 different trim levels and 5 color choices, there will be total (40 × 5) = 200 options one could choose. ( Answer )

4 0
3 years ago
A number,n,is multiplied by -5/8. The product is -0.4. What is the value of n?
Over [174]
N(-5/8)=-0.4
times both sides by -8/5
n(-40/-40)=3.2/5
n1=0.64
n=0.64
8 0
3 years ago
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A carpenter built three bookcase
Oduvanchick [21]
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6 0
3 years ago
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Consider triangle ABC. The legs have a length of 5 units each. What is the length of the hypotenuse of the triangle?
Korvikt [17]

Answer:

5\sqrt{2} units.

Step-by-step explanation:

We have been given that two legs of triangle ABC measures 5 units each. We are asked to find the length of the hypotenuse.

We will use Pythagoras theorem to solve for the hypotenuse of triangle ABC.

\text{Hypotenuse}^2=\text{Leg}^2+\text{Leg}^2

Substituting our given values in above equation we will get,

\text{Hypotenuse}^2=5^2+5^2

\text{Hypotenuse}^2=25+25

\text{Hypotenuse}^2=50

Upon taking square root of both sides of our equation we will get,

\text{Hypotenuse}=\sqrt{50}

\text{Hypotenuse}=\sqrt{25*2}

\text{Hypotenuse}=5\sqrt{2}

Therefore, the length of hypotenuse of triangle ABC is 5\sqrt{2} units.

6 0
3 years ago
Read 2 more answers
Please help i need to finish
elena-s [515]

Answer:

B. \overline A \overline C \cong \overline B \overline D

Step-by-step explanation:

The hypotenuse leg theorem (HL) requires the proof that the hypotenuse and the corresponding leg of the triangles to be equal in length. From the diagram, it can be found that \overline D \overline C is a common (shared) side of both triangles, so the additional fact needed is for the hypotenuses to be the same length.

∴ \overline A \overline C \cong \overline B \overline D is the additional fact needed to prove \triangle ADC \cong \triangle BCD

Hope this helps :)

5 0
3 years ago
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