Answer:
Step-by-step explanation:
- given λ =one for every 20minutes = 60/20 = 3customers/hr
- μ = average of 15minutes = 60/15 = 4customers/hr
a) percentage when judy was idle = 1- λ/μ = 1- 0.75 = 0.25
%service time = 0.75
%idle time = 0.25
b) How much time, on average, does a student spend waiting in line;
= λ/ μ( μ- λ)
= 0.75hrs = 0.75 x60 = 45minutes
c) How long is the waiting line on average;
= average waiting time x arrival rate = 0.75hrs x 3 customers/hr
= 2.25customers
d) What is the probability that an arriving student will find at least one other student waiting in line ; Po( probability of idle time i.e no customer to attend to) = 0.25
P1( Probability of having a customer to attend to) = 0.25 x 0.75 = 0.1875
P2( Probability of having 2 customer to attend to) = o.25 x 0.75x0.75 = 0.14
Hence, probability of finding at least one customer = 1 -[ po + p1]
= 1 - 0.25 - 0.1875 = 0.5625
Step-by-step explanation:
a. y = ¾x +6
b. y = 6/4 x -2
c. y = -2/4 x +3
d. y = -1/7 x -4
I think k divided by 2 so D.
Answer: Choice A
A translation 4 units to the left followed by a dilation by 2
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Explanation:
The following transformations will make the pre-image and image congruent to one another:
- Reflection
- Rotation
- Translation
If you apply any of those transformations mentioned above, then the image is an identical copy of the pre-image. Nothing about the figure has changed other than it has been shifted, rotated, or reflected in some way. The figure retains its original size and shape. These transformations are called isometries.
A dilation on the other hand does not preserve the size. "Dilation by 2" means the scale factor is 2, so the image will be twice as large compared to the pre-image, in terms of linear dimension. This means there is no way the image is congruent to the pre-image if a dilation has occurred.
Based on all this, choice A is the answer. Choices B, C, and D only involve the three isometries mentioned earlier and no dilation at all, so they can be ruled out.
Answer:
8x7
Step-by-step explanation: