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disa [49]
4 years ago
13

I need help finding the answer

Mathematics
2 answers:
sweet-ann [11.9K]4 years ago
8 0
Both missing angles are 65 degrees because a triangle equals 180 degrees and a straight line equals 180 degrees :) I hope this helped!
Anettt [7]4 years ago
4 0

Answer:

B = 65°

2 = 65°

Step-by-step explanation:

50° + 65° + B = 180°

115° + B = 180°

B = 65°

50° + 65° + 2 = 180°

115° + 2 = 180°

2 = 180° - 115°

2 = 65°

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Paul made 7 homemade pizzas. He used 3/4 of a cup of sauce for each pizza. How many cups of sauce did he use altogether?
hodyreva [135]

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5 1/4 cups

Step-by-step explanation:

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8 0
3 years ago
Is the equation y=2x a function
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3 0
3 years ago
Read 2 more answers
Anthony wants to buy CD for $400 that earns 2.5% APR and is compound quarterly. The CD matures in 3 years. Hi interest earned wi
lukranit [14]

Answer:

<em>The correct option is:   B.  $30.00</em>

Step-by-step explanation:

<u>The formula for compound interest</u> is.......

A=P(1+\frac{r}{n})^n^t , where A= Final amount, P= Initial amount, r= rate of interest in decimal form, n= number of compounding in a year and t= time duration in years.

Anthony wants to buy CD for $400 that earns 2.5% APR and is compound quarterly and the CD matures in 3 years.

So here,  P= 400, r=2.5\%=0.025, t= 3

As the CD is compounded quarterly, so here  n= 4

Plugging these values into the above formula......

A= 400(1+\frac{0.025}{4})^(^4^*^3^)\\ \\ A= 400(1+0.00625)^1^2\\ \\ A=400(1.00625)^1^2\\ \\ A= 431.053...

So, the amount of total interest earned = (\$431.053...-\$400)=\$31.053... \approx \$30.00(Approximately)

5 0
3 years ago
[PLEASE ANSWER] Precalculus Question (has 2 parts)
artcher [175]
Part I

\bf \begin{array}{l|lllllll}&#10;x&2&\boxed{4}&6&8&\boxed{10}&12&14\\\\&#10;y&1&\boxed{6}&11&16&\boxed{21}&26&31&#10;\end{array}\implies &#10;\begin{array}{llll}&#10;(4,6)\\\\&#10;(10,21)&#10;\end{array}\\\\&#10;-------------------------------\\\\

\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;&({{ 4}}\quad ,&{{ 6}})\quad &#10;%   (c,d)&#10;&({{ 10}}\quad ,&{{ 21}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{21-6}{10-4}


part II

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad &#10;\begin{array}{llll}&#10;\textit{plug in the values for }&#10;\begin{cases}&#10;y_1=6\\&#10;x_1=4\\&#10;m=\boxed{?}&#10;\end{cases}\\&#10;\end{array}\\&#10;\left. \qquad   \right. \uparrow\\&#10;\textit{point-slope form}


now, the form above is the point-slope form, and that'd be the equation, you can leave it like so, or you can solve for "y", and put it in slope-intercept, same equation though.
3 0
3 years ago
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