We can solve this problem using the law of conservation of energy.
This law states that energy in a closed system must stay same.
That means that the energy of a ball leaving the hand and the energy of a ball when it reaches its maximum height must be the same.
The energy of a ball leaving the players hand is kinetic energy:

The energy when the ball reaches its maximum height ( and has zero velocity) is potential energy in a gravitational field:

As said before these energies must be the same, and that allows us to find the initial speed:

When we plug in all the number we get that
We Know,
K.E. = 1/2 mv²
480 = 1/2 (m)(8)²
m = 960/64
m = 15 Kg
So, the mass of the object is 15 Kg
The answer to that is c hope it helps
Answer:
The maximum speed of the heart wall during the motion is 0.032 m/s
Explanation:
Given:
A = amplitude of vibration = 1.7 mm = 1.7x10⁻³m
f = frequency = 3 Hz
The angular velocity is:

The maximum speed of the heart wall during the motion is equal to:

higher temp = higher energy = higher frequency = shorter wavelength