Four radioactive 10-gram (g) samples with their remaining isotope mass are listed in the table that spans 50 years.

According to the Doppler effect what appears to happen when a light source moves further away from an observer

ludmilkaskok [199]

Answer: The correct answer is B. "the electromagnetic waves appear more red in color".

Explanation:

Scientists use the Doppler effect to understand the universe by determining the motion of the object.

Red shift: The apparent frequency of light decreases as the source object in space moves away from us. The light is shifted to red end. The apparent frequency decreases and there is increase in the wavelength of the light.

Blue shift: The apparent frequency of light increases as the object in space moves towards us. The light is shifted to blue end. In this case, there is decrease in the wavelength of the light. The frequency of the wave increases.

In the given problem, when the light source moves further away from an observer, the electromagnetic waves appear red in color.

Therefore, the correct option is (B).

6 0

3 years ago

Read 2 more answers

Hey how has ur morning gone?

victus00 [196]

Answer:

good

Explanation:

6 0

2 years ago

Earth has a surface area of 197 million square miles. Convert this area into each of the following units.

slamgirl [31]

Answers:

a) $510,225,121.4 km^{2}$

We know the Earth's surface area in square miles is:

$197000000 mi^{2}$

On the other hand, we know $1 mi=1.60934 km$ .

Then:

$197000000 mi^{2} \frac{(1.60934 km)^{2}}{1 mi^{2}}=510,225,121.4 km^{2}$

b) $510.225 Mm^{2}$

In this part, we can work with the obtained value in part a:

$510,225,121.4 km^{2}$

And knowing $1 km=0.001 Mm$

Hence:

$510,225,121.4 km^{2} \frac{(0.001 Mm)^{2}}{1 km^{2}}=510.225 Mm^{2}$

c) $5.1022(10)^{16} dm^{2}$

Knowing $1 Mm=10^{7} dm$ :

$510.225 Mm^{2} \frac{(10^{7} dm)^{2}}{1 Mm^{2}}=5.1022(10)^{16} dm^{2}$

7 0

3 years ago

When an airplane is flying 200 mph at 5000-ft altitude in a standard atmosphere, the air velocity at a certain point on the wing

Sedaia [141]

Answer:

P1 = 0 gage

P2 = 87.9 lb/ft³

Explanation:

Given data

Airplane flying = 200 mph = 293.33 ft/s

altitude height = 5000-ft

air velocity relative to the airplane = 273 mph = 400.4 ft/s

Solution

we know density at height 5000-ft is 2.04 × $10^{-3}$ slug/ft³

so here P1 + $\frac{\rho v1^2}{2}$ = P2 + $\frac{\rho v2^2}{2}$

and here

P1 = 0 gage

because P1 = atmospheric pressure

and so here put here value and we get

P1 + $\frac{\rho v1^2}{2}$ = P2 + $\frac{\rho v2^2}{2}$

0 + $\frac{2.048 \times 10^{-3} \times 293.33^2}{2}$ $= P2 + \frac{2.048 \times 10^{-3} \times 400.4^2}{2}$

solve it we get

P2 = 87.9 lb/ft³

5 0

3 years ago

How many grams of calcium metal is required to react with 7.75 g water to produce calcium hydroxide and hydrogen gas?

Gekata [30.6K]

87.69 grams of calcium metal is required to react with 7.75 g water to produce calcium hydroxide and hydrogen gas.

Ca (OH)2+2H2 = CaH2 + 2H2O

Convert grams of hydrogen to moles of hydrogen.

H2 has a molar mass of 2.016 g/mol.

1 mol H2 x 8.400g H2

2.016g H2 equals 4.1667 mol H2

Calculate the moles of CaH2 using the molar ratio.

The molar ratio is 1 mol CaH2: 2 mol H2, according to the equation that is balanced.

2.0833 mol CaH2 = 4.1667 mol H2 1 mol CaH2 2 mol H2

grams of CaH2 to CaH2

CaH2 has a molar mass of 42.09 g/mol.

1.mol CaH2=87.69 g CaH2 2.0833mol CaH2=42.09 g CaH2

87.69 g CaH2 are required for the reaction.

Learn more about moles here-

brainly.com/question/26416088

#SPJ4

7 0

2 years ago