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HACTEHA [7]
3 years ago
11

A 0.10 kg meter stick is held perpendicular to a vertical wall by a 2.5 mm string going from the wall to the far end of the stic

k.
(A) Find the tension in the string.
(B) If a shorter string is used, will its tension be greater than, less than, or the same as that found in part (A)?
(C) Find the tension in a 2.0 m string.
Physics
1 answer:
il63 [147K]3 years ago
6 0

Explanation:

a)

Sum of moments = 0 (Equilibrium)

T . cos (Q)*L = m*g*L/2

cos Q = \frac{\sqrt{(2.5^2 - L^2) } }{2.5}

T*\frac{\sqrt{(2.5^2 - L^2) } }{2.5} * L = 0.1 *9.81*L/2

T = \frac{2.4525}{\sqrt{(2.5)^2 - L^2} }

b) If the String is shorter the Q increases; hence, Cos Q decreases which in turn increases Tension in the string due to inverse relationship!

c)

T = \frac{1.962}{\sqrt{(2)^2 - L^2} }

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m = 24.2 kg

<h3>What is the person's mass?</h3>

Generally, the equation for the conservation  angular momentum  is mathematically given as

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m = 24.2 kg

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2 years ago
What nuclear reaction is the energy source of a white dwarf?
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Nuclear Fusion

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3 years ago
If you weigh 660 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun an
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Answer:

8.93*10^13 N.

Explanation:

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3 years ago
A rocket moves upward from rest with an acceleration of 40 m/s2 for 5 seconds. It then runs out of fuel and continues to move up
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Now let us find out time after 5 seconds rocket move upward.

We have the equation of motion v = u + at

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