What is the surface area of this figure?

I) the probability that the person is female is 8.33%.
II) the probability that the person has a risk factor heterosexual contact is 6.40%.
III) the probability that the person is female or has a risk factor of IV drug user is 23.47%.
IV) the probability that the person is female and has a risk factor of homosexual is 0%.
V) the probability that the person is male and has a risk factor of IV drug user is 15.13%.
VI) the probability that the person is female given that the person got the disease from heterosexual contact is 69.38%.

Given the data mentioned in the table, the following calculations must be performed to obtain the requested probabilities:

I.-

(0 + 70 + 136 + 49) / (2,146 + 463 + 60 + 135 + 0 + 70 + 136 + 49) = X

255/3059 = X

0.0833 = X

II.-

196/3059 = X

0.0640 = X

III.-

(255 + 463) / 3059 = X

718/3059 = X

0.2347 = X

IV.-

0/3059 = X

0 = X

V.-

463/3059 = X

0.1513 = X

VI.-

136/196 = X

0.6938 = X

Therefore, I) the probability that the person is female is 8.33%, II) the probability that the person has a risk factor heterosexual contact is 6.40%, III) the probability that the person is female or has a risk factor of IV drug user is 23.47%, IV) the probability that the person is female and has a risk factor of homosexual is 0%, V) the probability that the person is male and has a risk factor of IV drug user is 15.13%, and VI) the probability that the person is female given that the person got the disease from heterosexual contact is 69.38%.

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