Answer:
Create a table.
Plug values into the equation to complete the table.
Use the table to plot points on the graph.
Draw lines through the points on your graph.
The graph should look linear because there is an x that doesn't have a power greater than or less than 1.
Answer: y = 3/2x + 1
Step-by-step explanation: For a perpendicular line, take the reciprocal of "m" and reverse the sign.
- 2/3 becomes +3/2
Then substitute the y and x values of the given coordinate into the equation and solve for "b"
y = mx + b
-2 = 3/2(-2) + b
-2 = -3 + b
-2 +3 = b
+1 = b Substitute for b in y = (3/2)x + 1
29.70 because you multiply 10 x 297 and you get 2970 just input your decimal which is 29.70
Answer:
The running time is quadratic (O(n²) )
Step-by-step explanation:
For the set up, we have a constant running time of C. The, a log-linearsorting is called, thus, its execution time, denoted by T(n), is O(n*log(n)). Then, we call n times a linear iteration, with a running time of an+b, for certain constants a and b, thus, the running time of the algorithm is
C + T(n) + n*(a*n+b) = an²+bn + T + C
Since T(n) is O(n*log(n)) and n² is asymptotically bigger than n*log(n), then the running time of the algorith is quadratic, therefore, it is O(n²).
C/20 cups flour in one cake is the term.
Step-by-step instructions: * First, let's go over how to solve the problem: - There are ten students; each produced two chocolate cakes; they all used the same recipe; the total amount of flour used is C cups * Let's put this information into an equation: There are ten pupils, and each of them produced two cakes. The total number of cakes is ten plus two, for a total of twenty cakes
