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Julli [10]
3 years ago
15

What is the molecular formula for hydrogen peroxide?

Chemistry
1 answer:
Strike441 [17]3 years ago
5 0
The answer is “H2O2” .....
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2. The combustion of heptane (C7H16) in oxygen spontaneously occurs. The products of the reaction are carbon dioxide and water v
masya89 [10]

The combustion of heptane (C7H16) in oxygen spontaneously occurs. The products of the reaction are carbon dioxide and water vapor. The balanced chemical equation is 7H16 + 11O2 → 7CO2 + 8H2O H = –2877.5 kJ.

8 0
3 years ago
Which of these objects have potential energy?
Korolek [52]

Answer:

it's C. but the sentence is incorrect I think it should be a ball "in" someone's hand

Explanation:

cause potential energy is the energy that is stored in an object due to its position relative to some zero position. An object possesses gravitational potential energy if it is positioned at a height above (or below) the zero height.

8 0
3 years ago
Grace injured her ankle while running a relay race at the family reunion. Her aunt breaks the inner, activator portion of an ins
Solnce55 [7]

Answer:

A

Explanation:

8 0
3 years ago
If you push on a cart, the force of friction will slow it down. Friction is
meriva

Answer:

Heat

Explanation:

Friction can help convert heat into kinetic energy and kinetic energy into heat. Friction can be thought of as particles from different objects hitting each other. Collisions transfer energy converting large scale movement (kinetic energy) into small scale movement (heat).

6 0
3 years ago
Hydrogen is diffusing through solid nickel. At a temperature of 358 K, the diffusivity is 1.16 x 10-8 cm2/s. At a temperature of
Lelu [443]

Answer:

Q_d=35881 J/mol

So the activation energy is 35881 J/mol.

Explanation:

Consider the following equations:

lnD_{1} =lnD_{o} -\frac{Q_{d} }{R*T_{1} }

lnD_{2} =lnD_{o} -\frac{Q_{d} }{R*T_{2} }

Solving the above two equation to find the Q_d in term of diffusivity and temperature we will get:

Q_{d}=-R*\frac{lnD_{1} -lnD_{2} }{\frac{1}{T_{1} }-\frac{1}{T_{2} }  }

where:

Q_d is the activation energy

D_1 is the diffusivity at T_1

D_2 is the diffusivity at T_2

Q_{d}=-8.31*\frac{ln1.16*10^-12 -ln1.05*10^-11 }{\frac{1}{358 }-\frac{1}{438 }  }

Q_d=35881 J/mol

So the activation energy is 35881 J/mol.

3 0
4 years ago
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