Answer:
Last year there were 550 bison in the heard and this year it is 10% larger.
10% is also 10/100 or 0.10
To find 10% of the heard last year
550 x.0.10 = 55. To find the number in the heard this year add 550 (last year) + 55 (10% growth) = 605 or,
to find how many there are now last years heard size was 100% of the heard or 1.00. To find any percent more add it to 1.00 and multiply by the starting amount.
550 x 1.10 = 605
For the second example.
If there are 550 bison in the heard this year, and this year was a decrease of 10% from last year we can express last year's number like this.
550 = (x - (x * 0.10)) simplify;
550 = 1x - 0.10x
550 = 0.90x
Divide both sides by 0.90
x = 611.11 but it's hard to have 0.11 of a bison so realistically 611 bison last year. Subtract 10% or 61 and you indeed have 550 this year.
Answer:
1/3
Step-by-step explanation:
I'm not to sure but if there is 12 slices and the 2 each had 2 of there own slices, this would be 4/12 simplified into 1/3.
If you're taking trig, the "sum and difference formulas for trig functions" are basic facts that you'll need to learn and commit to memory. I'd suggest you look up these formulas on the net. You will likely immediately find listings for the sine, cosine and tangent.
<span>Standard deviation of first data set = 5879.1
Standard deviation of second data set = 14768.78
The second data set is more variable.
The basic definition of standard deviation is the square root of the mean of the squares of the difference from the mean. It's a bit of a mouthful, but easy enough to do. For the first data set, first calculate the mean.
(28995 + 37534 + 31361 + 27087 + 20966 + 37741) / 6 = 30614
Now calculate the square of the differences from the mean
(28995 - 30614)^2 = 2621161
(37534 - 30614)^2 = 47886400
(31361 - 30614)^2 = 558009
(27087 - 30614)^2 = 12439729
(20966 - 30614)^2 = 93083904
(37741 - 30614)^2 = 50794129
And now the average of the squares
(2621161 + 47886400 + 558009 + 12439729 + 93083904 +50794129) / 6 = 34563888.67
And finally, take the square root to get the standard deviation.
sqrt(34563888.67) = 5879.1
Now for the second data set of western states. First, the mean
(72964 + 70763 + 101510 + 62161 + 66625 + 54339) / 6 = 71393.67
Now the squares of the differences
(72964 - 71393.67)^2 = 2465946.778
(70763 - 71393.67)^2 = 397740.4444
(101510 - 71393.67)^2 = 906993533.4
(62161 - 71393.67)^2 = 85242133.78
(66625 - 71393.67)^2 = 22740181.78
(54339 - 71393.67)^2 = 290861655.1
And the average of the squares is 218116865.2
Finally, the square root of the average is 14768.78
So the standard deviation of the 2nd data set is 14768.78
And since the standard deviation of the 2nd data set is larger than the standard deviation of the 1st data set, that means that the 2nd data set is more variable.</span>
