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3 years ago

True or False. Light is a form of energy.

Physics

2 answers:

ExtremeBDS [4]3 years ago

5 0

trueee...................

Xelga [282]3 years ago

5 0

Answer:

true

Explanation:

light is a form of energy which is radiation so true:)

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bonnie pulls a cart that weighs 195 N with a force of 18.0 N. According to Newton's 3rd law, with what force does the cart pull

motikmotik

Answer:

The force exerted by the cart on Bonnie is - 18.0 N

Explanation:

Given;

weight of the cart, w = 195 N

Bonnie's applied force on the cart, F = 18.0 N

According to Newton's 3rd law, action and reaction are equal and opposite.

Thus, the cart will pull back at Bonnie with force of equal magnitude but in opposite direction.

The force exerted by the cart on Bonnie = - 18.0 N

4 0

3 years ago

We are able to walk forward because _____.

Diano4ka-milaya [45]

Cuz Of Newton’s third law, every actions there is an equal and opposite reaction.

7 0

3 years ago

Read 2 more answers

Help!! ASAP plz

VashaNatasha [74]

Can you include an image of the object and it’s dimensions?

4 0

3 years ago

A projectile is fired horizontally from a height of 10 m above level ground. The projectile lands a horizontal distance of 15 m

Degger [83]

Answer:

a)t = 1,43 s

b) V = 10,49 m/s

c) V₀ₓ = 10,49 m/s ; V₀y = 14,01 m/s

d) Vf = 17,5 m/s

Explanation:

According to the problem statement

V₀ = V₀ₓ and V₀y = 0

And at the end of the movement t = ? the distance y = 10 m

Therefore as

h = V₀y - (1/2)*g*t²

Vertical distance y = h = 10 = V₀y*t - 0,5 (-9,8)*t²

10 = 4,9*t²

t² = 10/4,9 ⇒ t² = 2,04 s

t = 1,43 s

a) 1,43 s is the time of movement

b) V₀ = V₀ₓ V₀y = 0 and V₀ₓ = Vₓ ( constant )

Just before touching the ground, the horizontal distance is

hd = 15 = Vₓ * t

Then 15 /1,43 = Vₓ = V₀ₓ

Vₓ = 10,49 m/s

Then initial speed is V = 10,49 m/s since V₀y = 0

Vf² = Vₓ² + Vy²

Vyf = V₀y - g*t

Vyf = 0 - 9,8 *1,43

Vyf = - 14,01 m/s

And finally the speed when the projectile strike the ground is:

Vf² = Vₓ² + Vy²

Vf = √ (10,49)² + (14,01)²

Vf = 17,50 m/s

3 0

4 years ago

Q 17.10: Receiver A detects a sound level of 75 dB at a distance of 25 m from a speaker, which emits sound equally in all direct

Ronch [10]

Answer:

250 m

Explanation:

We expect the distance to be more because the sound level has decreased.

Sound level (in decibels) is related to distance by

$r_2 = r_1 \times 10^{\frac{|L_1-L_2|}{20}}$

where $L_1$ is the sound level at a distance of $r_1$ and

$L_2$ is the sound level at a distance of $r_2$ .

Using the values in the question,

$r_{2} = 25\times10^{\frac{|75-55|}{20}} \text{ m}$

$r_2 = 25\times10^1 \text{ m}= 250 \text{ m}$

As a note, when distance increases by 10, the sound level drops by 20 dB, which is what we have in the question.

4 0

3 years ago