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icang [17]
3 years ago
15

Q 17.10: Receiver A detects a sound level of 75 dB at a distance of 25 m from a speaker, which emits sound equally in all direct

ions. Receiver B detects a sound level of 55 dB from the same speaker. How far is receiver B from the speaker
Physics
1 answer:
Ronch [10]3 years ago
4 0

Answer:

250 m

Explanation:

We expect the distance to be more because the sound level has decreased.

Sound level (in decibels) is related to distance by

r_2 = r_1 \times  10^{\frac{|L_1-L_2|}{20}}

where L_1 is the sound level at a distance of r_1 and

L_2 is the sound level at a distance of r_2.

Using the values in the question,

r_{2} = 25\times10^{\frac{|75-55|}{20}} \text{ m}

r_2 = 25\times10^1 \text{ m}= 250 \text{ m}

As a note, when distance increases by 10, the sound level drops by 20 dB, which is what we have in the question.

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All Houston Methodist buildings system wide have an emergency power generator that turns on to supply emergency power after norm
lesya692 [45]

Answer:

D. 10 seconds

Explanation:

All Houston Methodist Hospital buildings employs the use of EPSS(Emergency Power Supply System). This system employs the use of an emergency power generator that turns on to supply emergency power after normal power shuts down within 10 seconds during power outage.

Due to it being used in a hospital the importance of this emergency power system cannot be overemphasized as it is used to provide power supply to hospital equipment such as life support machines etc.

3 0
3 years ago
A skater of mass 40 kg is carrying a box of mass 5 kg. The skater has a speed of 5 m/s with respect to the floor and is gliding
Yuki888 [10]

For the part a) we need only the momentum of the box and we have the data to find it.

Momentum is given by,

p=mv

where clearly, p is the momentum, m the mass of the box and v is the velocity.

Substituting,

p=(5kg)(5m/s)\\p=25kg.m/s

For part b) we need an analysis of the situation. We understand that the box on a surface that has no friction will continue to rotate at the same speed previously defined. The box can only stop with friction, so,

p=(5kg)(5m/s)\\p=25kg.m/s

<em>It is the same that part a)</em>

8 0
3 years ago
g We saw in class that in a pendulum the string does no work. We also saw that the normal force does no work on an object slidin
Ymorist [56]

Answer:

From question (a) and (b) the pendulum motion is perpendicular to the force so the normal force will do no work and the tension in the string of the pendulum will not work

       i.e Normal \ Force(N)  = mg cos \theta

And \theta = 90 so

           N = 0

c

An example will be a where a stone is attached to the end of a string and is made to move in a circular motion while keeping the other end of the string in a fixed position        

d

A dog walking along a surface which has friction, here the frictional force would acting in the direction of the motion and this would do positive work  

Explanation:

5 0
3 years ago
Read 2 more answers
How much kinetic energy is in a 0.145kg baseball thrown at 35.8 m/s ?
Mazyrski [523]
K= (1/2) m v^2
so 0.5*0.145*<span>1281.64=92.92J of KE</span>
4 0
4 years ago
If anyone help this question I getting wrong answer. I don’t know why I keep getting wrong. Could anyone help me please?! Please
pishuonlain [190]
Slope formula : y2 - y1 / x2 - x1 

The coordinates are ( 66 , 39)  and ( 12 , 83)

 
                        83 - 39 /  12 - 66 

                            44 / - 54 

                  slope = - 0 . 81 or - 22/27

                        
5 0
3 years ago
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