Answer:
54 i think
Step-by-step explanation:
The answer should be 26 hours
Answer:
The center of the circle is at;

The radius of the circle is;

Explanation:
Given the equation of circle;

we want to re-write it in the form;

where;

Applying Completing the square method;

comparing the derived equation to the general form we have;

Therefore;
The center of the circle is at;

The radius of the circle is;
I believe it’s 9
If i’m wrong i’m sorry!
God bless
Answer:
(y - 2) and (x + 3)
Step-by-step explanation:
(y - 2)(x + 3) is already in factored form; the factors are (y - 2) and (x + 3).