Duracell batteries are an example of an electrochemical cell that is powered between the reaction of Magnesium and Zinc, occurring in basic conditions (alkaline battery). This type of reaction has a precise output of 1.5 volts, and looks like this:
Zn + 2MnO2 ➡️ ZnO + Mn2O3
It’s not rechargeable.
Golf Cart Batteries are an example of an electrochemical cell that is powered by the reaction between Lead and Sulfuric Acid (Lead-Acid battery). This type of reaction occurs on larger scales than an alkaline battery, and thus can generate a variety of powers depending on how many instruments are present within the battery. The reaction looks like this:
PbO2 + Pb + 2H2SO4 ➡️ 2PbSO4 + H2O
This is a rechargeable cell, but is rather prone to discharging by the environment and surroundings of the battery.
Answer:
Current in resistors = 1.5 amp
Current in resistors = 0.18 amp
P = 93.75 watts
Explanation:
Given:
1. Three 5 ohm resistor(series)
Voltage = 10 volt
2. Three 5 ohm resistor(parallel)
Voltage = 9 volt
3. Three 5 ohm resistor(series)
Voltage = 6 volt
Find:
Current in resistors
Current in resistors
Total power of circuit
Computation:
1. Total resistor (Series) R = R1 + R2 + R3
Total resistor (Series) R = 5 + 5 + 5
Total resistor (Series) R = 15 ohm
I = V/R
Current in resistors = (15)/(10)
Current in resistors = 1.5 amp
2. Total resistor (Series) R = 1/[1/R1 + 1/R2 + 1/R3
Total resistor (Series) R = 1[1/5 + 1/5 + 1/5]
Total resistor (Series) R = 1.67 ohm
I = V/R
Current in resistors = (1.67)/(9)
Current in resistors = 0.18 amp
3. Total resistor (Series) R = R1 + R2 + R3
Total resistor (Series) R = 5 + 5 + 5
Total resistor (Series) R = 15 ohm
I = V/R
I = (15)/(6)
I = 2.5 amp
P = I²(R)
P = (2.5)²(15)
P = 93.75 watts
Answer:
a). la acelaración del automóvil es
b). la distancia recorrida por el automóvil es
La aceleración puede ser encontrada por medio de la ecuación cinemática que corresponde a un movimiento rectilíneo uniformemente variado.
(1)
Donde es la velocidad final y es la velocidad inicial.
La velocidad inicial del automóvil sera cero () ya que parte del reposo.
Antes de remplazar los valores en la ecuación 1 es necesario expresar el tiempo en unidades de segundos.
⇒
La rapidez final puede ser expresada en unidades de :
Por lo tanto, la acelaración del automóvil es
Luego para calcular la distancia se puede utilizar la siguiente ecuación.
(2)
Por lo tanto, la distancia recorrida por el automóvil es
Answer:
19.2m/s
Explanation:
Assuming that 2.4m/s^2 was the acceleration and not a typo, we can use the equation v=at, where v=velocity, a=acceleration, and t=time,
plug in known varibles,
v=2.4*8
v=19.2m/s