F = kq1q2/r^2
<span>q1 is first charge </span>
<span>q2 is second charge </span>
<span>k is 9 E9 </span>
<span>r is distance between them </span>
<span>F = (9E9)(2 E-6)(4 E-6)/2^2 = 0.018 N </span>
<span>A postive answer indicates a repulsive force</span>
Because the gravitational field strength on the moon (1.6N/kg)is smaller than the gravitational field strength on the earth (9.8N/kg). Weight= mass×gravitational field strength. Your mass is the same but as g is smaller, your weight decreases. weight is the gravitational force, the downwards force towards the centre of the planet, and as it will be smaller on the moon, the force of attraction between the moon and you is smalller so when you jumb you will reach a higher point above the ground than when you jumb on the earth. Basically the moon 'pulls' you less than the earth.
Answer:
The magnitude of the applied force is 94.74 N
Explanation:
Mass of the block, m = 11 kg
Angle of inclination of the plane, 
Friction coefficient, 
Now,
Normal force that acts on the block is given by:
(1)
Now, to maintain the equilibrium parallel to ramp the forces must be balanced.
Thus
(2)
From eqn (1) and (2)
F = 94.74 N
Answer:
240000 mph² or miles/hour²
Explanation:
<em>Use the formula</em>
<h3>acceleration = change in velocity ÷ time</h3>
change in velocity = 300 mph - 0 mph (final velocity - intial velocity)
time = 0.00125 hours
<em>Substitute the values into the formula:</em>
acceleration = 300 ÷ 0.00125 = 240000 mph²
A WAN
I just did it, let me know if it was right :)
