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2 years ago

Why does a solar and lunar eclips not happen every month

Physics

1 answer:

jasenka [17]2 years ago

4 0

Answer:

"because the Moon's orbit is tilted five degrees from Earth's orbit around the Sun, so most of the time the Moon passes above or below the shadow."

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On a cold winters da,y,If you left a drink setting outside,it could freeze.Explain why in a complete sentence

sertanlavr [38]

Hello!

On a cold winters day, if you left a drink setting outside, it could freeze because the heat (related to the kinetic energy) of the atoms in the drink will be transferred to the environment to achieve energy equilibrium.

Heat transfer occurs by various mechanisms, flowing from the hottest body to the coldest, that's why the heat goes from the drink, which has a higher temperature (and kinetic energy) to the environment, which has a lower temperature. This is described by the second law of thermodynamics

6 0

4 years ago

En una práctica un beisbolista lanza verticalmente la bola con una velocidad de 12m/s en dirección ascendente. ¿Cuál será la alt

fgiga [73]

Answer:

Thus, the maximum height is 7.35 m.

Explanation:

initial velocity, u = 12 m/s

acceleration due to gravity, g = 9.8 m/s^2

Velocity at maximum height, v = 0 m/s

Let the maximum height is h.

Use third equation of motion

$v^{2}=u^{2}-2 g h\\0 = 12\times 12 - 2 \times 9.8\times h\\h =7.35 m$

8 0

3 years ago

5. If x = 0.6 and y = 5, the value of 2(xy)^3 is...

taurus [48]

Explanation:

=2(0.6 * 5)³

=2( 3 )³

=2(27)

=54

3 0

3 years ago

Read 2 more answers

What is kinematics?<br>explain!!~<br><br>thankyou ~

artcher [175]

Answer:

Kinematics is the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.

-the features or properties of motion in an object.

Explanation:

Hope this helps <3

Have a great day!

7 0

2 years ago

Read 2 more answers

A small racquet ball launcher is set up 5 meters from a 12 meter tall wall. It launches a racket ball at 30 m/s at an angle of 4

Strike441 [17]

Answer:20.82 m

Explanation:

Given

distance between wall and launcher=5 m

initial velocity=30 m/s

Launching angle $=45^{\circ}$

Height of wall=12 m

maximum height by ball

$h_{max}=\frac{u^2sin^2\theta }{2g}$

$h_{max}=\frac{30^2sin^{2}45}{2\times 9.8}$

h=22.95 m

$y=xtan\theta -\frac{gx^2}{2u^2cos^\theta }$

y=4.72 m

so ball will strike with wall

and for perfect restitution final velocity of ball will be same as the horizontal velocity before its impact, only direction will be opposite and vertical velocity will be zero

thus it seems as if someone throw the ball with horizontal velocity of 30cos45 from a height of 4.72

Time required to cover 4.72 m

$t=\sqrt{\frac{2h}{g}}$