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Oliga [24]
3 years ago
15

If the average velocity during the athlete's walk back

Physics
1 answer:
goblinko [34]3 years ago
4 0

Hence ,From the Guide there are other parameters which with this equation will give the exact time the athlete's walk back

T=\frac{d}{1.50}

From the question we are told

If the average velocity during the athlete's walk back  to the starting line in Guided Example 2.5 is – 1.50 m/s,

Generally the equation Time spent  is mathematically given as

T=\frac{d}{v}

Therefore

T=\frac{d}{1.50}

Hence ,From the Guide there are other parameters which with this equation will give the exact time the athlete's walk back

T=\frac{d}{1.50}

For more information on this visit

brainly.com/question/22271063

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Answer:

B. and D. would be my best guess.

Explanation:

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alekssr [168]
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<span>jill ------------------------------- force of 89.9 n   northeast
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</span>Fjill(Y)=sin45*89.9=63.57 n<span>

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